Metamath Proof Explorer


Theorem fzen

Description: A shifted finite set of sequential integers is equinumerous to the original set. (Contributed by Paul Chapman, 11-Apr-2009)

Ref Expression
Assertion fzen ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → M … N ≈ M + K … N + K

Proof

Step Hyp Ref Expression
1 ovexd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → M … N ∈ V
2 ovexd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → M + K … N + K ∈ V
3 elfz1 ⊢ M ∈ ℤ ∧ N ∈ ℤ → k ∈ M … N ↔ k ∈ ℤ ∧ M ≤ k ∧ k ≤ N
4 3 biimpd ⊢ M ∈ ℤ ∧ N ∈ ℤ → k ∈ M … N → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N
5 4 3adant3 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ M … N → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N
6 zaddcl ⊢ k ∈ ℤ ∧ K ∈ ℤ → k + K ∈ ℤ
7 6 expcom ⊢ K ∈ ℤ → k ∈ ℤ → k + K ∈ ℤ
8 7 3ad2ant3 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ → k + K ∈ ℤ
9 8 adantrd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N → k + K ∈ ℤ
10 zre ⊢ M ∈ ℤ → M ∈ ℝ
11 zre ⊢ k ∈ ℤ → k ∈ ℝ
12 zre ⊢ K ∈ ℤ → K ∈ ℝ
13 leadd1 ⊢ M ∈ ℝ ∧ k ∈ ℝ ∧ K ∈ ℝ → M ≤ k ↔ M + K ≤ k + K
14 10 11 12 13 syl3an ⊢ M ∈ ℤ ∧ k ∈ ℤ ∧ K ∈ ℤ → M ≤ k ↔ M + K ≤ k + K
15 14 biimpd ⊢ M ∈ ℤ ∧ k ∈ ℤ ∧ K ∈ ℤ → M ≤ k → M + K ≤ k + K
16 15 adantrd ⊢ M ∈ ℤ ∧ k ∈ ℤ ∧ K ∈ ℤ → M ≤ k ∧ k ≤ N → M + K ≤ k + K
17 16 3com23 ⊢ M ∈ ℤ ∧ K ∈ ℤ ∧ k ∈ ℤ → M ≤ k ∧ k ≤ N → M + K ≤ k + K
18 17 3expia ⊢ M ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ → M ≤ k ∧ k ≤ N → M + K ≤ k + K
19 18 impd ⊢ M ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N → M + K ≤ k + K
20 19 3adant2 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N → M + K ≤ k + K
21 zre ⊢ N ∈ ℤ → N ∈ ℝ
22 leadd1 ⊢ k ∈ ℝ ∧ N ∈ ℝ ∧ K ∈ ℝ → k ≤ N ↔ k + K ≤ N + K
23 11 21 12 22 syl3an ⊢ k ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ≤ N ↔ k + K ≤ N + K
24 23 biimpd ⊢ k ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ≤ N → k + K ≤ N + K
25 24 adantld ⊢ k ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → M ≤ k ∧ k ≤ N → k + K ≤ N + K
26 25 3coml ⊢ N ∈ ℤ ∧ K ∈ ℤ ∧ k ∈ ℤ → M ≤ k ∧ k ≤ N → k + K ≤ N + K
27 26 3expia ⊢ N ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ → M ≤ k ∧ k ≤ N → k + K ≤ N + K
28 27 impd ⊢ N ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N → k + K ≤ N + K
29 28 3adant1 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N → k + K ≤ N + K
30 9 20 29 3jcad ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N → k + K ∈ ℤ ∧ M + K ≤ k + K ∧ k + K ≤ N + K
31 zaddcl ⊢ M ∈ ℤ ∧ K ∈ ℤ → M + K ∈ ℤ
32 31 3adant2 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → M + K ∈ ℤ
33 zaddcl ⊢ N ∈ ℤ ∧ K ∈ ℤ → N + K ∈ ℤ
34 33 3adant1 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → N + K ∈ ℤ
35 elfz1 ⊢ M + K ∈ ℤ ∧ N + K ∈ ℤ → k + K ∈ M + K … N + K ↔ k + K ∈ ℤ ∧ M + K ≤ k + K ∧ k + K ≤ N + K
36 32 34 35 syl2anc ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k + K ∈ M + K … N + K ↔ k + K ∈ ℤ ∧ M + K ≤ k + K ∧ k + K ≤ N + K
37 36 biimprd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k + K ∈ ℤ ∧ M + K ≤ k + K ∧ k + K ≤ N + K → k + K ∈ M + K … N + K
38 30 37 syldc ⊢ k ∈ ℤ ∧ M ≤ k ∧ k ≤ N → M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k + K ∈ M + K … N + K
39 38 3impb ⊢ k ∈ ℤ ∧ M ≤ k ∧ k ≤ N → M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k + K ∈ M + K … N + K
40 39 com12 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N → k + K ∈ M + K … N + K
41 5 40 syld ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ M … N → k + K ∈ M + K … N + K
42 elfz1 ⊢ M + K ∈ ℤ ∧ N + K ∈ ℤ → m ∈ M + K … N + K ↔ m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K
43 32 34 42 syl2anc ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ M + K … N + K ↔ m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K
44 43 biimpd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ M + K … N + K → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K
45 zsubcl ⊢ m ∈ ℤ ∧ K ∈ ℤ → m − K ∈ ℤ
46 45 expcom ⊢ K ∈ ℤ → m ∈ ℤ → m − K ∈ ℤ
47 46 3ad2ant3 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ ℤ → m − K ∈ ℤ
48 47 adantrd ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → m − K ∈ ℤ
49 zre ⊢ m ∈ ℤ → m ∈ ℝ
50 leaddsub ⊢ M ∈ ℝ ∧ K ∈ ℝ ∧ m ∈ ℝ → M + K ≤ m ↔ M ≤ m − K
51 10 12 49 50 syl3an ⊢ M ∈ ℤ ∧ K ∈ ℤ ∧ m ∈ ℤ → M + K ≤ m ↔ M ≤ m − K
52 51 biimpd ⊢ M ∈ ℤ ∧ K ∈ ℤ ∧ m ∈ ℤ → M + K ≤ m → M ≤ m − K
53 52 adantrd ⊢ M ∈ ℤ ∧ K ∈ ℤ ∧ m ∈ ℤ → M + K ≤ m ∧ m ≤ N + K → M ≤ m − K
54 53 3expia ⊢ M ∈ ℤ ∧ K ∈ ℤ → m ∈ ℤ → M + K ≤ m ∧ m ≤ N + K → M ≤ m − K
55 54 impd ⊢ M ∈ ℤ ∧ K ∈ ℤ → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → M ≤ m − K
56 55 3adant2 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → M ≤ m − K
57 lesubadd ⊢ m ∈ ℝ ∧ K ∈ ℝ ∧ N ∈ ℝ → m − K ≤ N ↔ m ≤ N + K
58 49 12 21 57 syl3an ⊢ m ∈ ℤ ∧ K ∈ ℤ ∧ N ∈ ℤ → m − K ≤ N ↔ m ≤ N + K
59 58 biimprd ⊢ m ∈ ℤ ∧ K ∈ ℤ ∧ N ∈ ℤ → m ≤ N + K → m − K ≤ N
60 59 adantld ⊢ m ∈ ℤ ∧ K ∈ ℤ ∧ N ∈ ℤ → M + K ≤ m ∧ m ≤ N + K → m − K ≤ N
61 60 3coml ⊢ K ∈ ℤ ∧ N ∈ ℤ ∧ m ∈ ℤ → M + K ≤ m ∧ m ≤ N + K → m − K ≤ N
62 61 3expia ⊢ K ∈ ℤ ∧ N ∈ ℤ → m ∈ ℤ → M + K ≤ m ∧ m ≤ N + K → m − K ≤ N
63 62 impd ⊢ K ∈ ℤ ∧ N ∈ ℤ → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → m − K ≤ N
64 63 ancoms ⊢ N ∈ ℤ ∧ K ∈ ℤ → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → m − K ≤ N
65 64 3adant1 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → m − K ≤ N
66 48 56 65 3jcad ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → m − K ∈ ℤ ∧ M ≤ m − K ∧ m − K ≤ N
67 elfz1 ⊢ M ∈ ℤ ∧ N ∈ ℤ → m − K ∈ M … N ↔ m − K ∈ ℤ ∧ M ≤ m − K ∧ m − K ≤ N
68 67 biimprd ⊢ M ∈ ℤ ∧ N ∈ ℤ → m − K ∈ ℤ ∧ M ≤ m − K ∧ m − K ≤ N → m − K ∈ M … N
69 68 3adant3 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m − K ∈ ℤ ∧ M ≤ m − K ∧ m − K ≤ N → m − K ∈ M … N
70 66 69 syldc ⊢ m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m − K ∈ M … N
71 70 3impb ⊢ m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m − K ∈ M … N
72 71 com12 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K → m − K ∈ M … N
73 44 72 syld ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ M + K … N + K → m − K ∈ M … N
74 5 imp ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ k ∈ M … N → k ∈ ℤ ∧ M ≤ k ∧ k ≤ N
75 74 simp1d ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ k ∈ M … N → k ∈ ℤ
76 75 ex ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ M … N → k ∈ ℤ
77 44 imp ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ m ∈ M + K … N + K → m ∈ ℤ ∧ M + K ≤ m ∧ m ≤ N + K
78 77 simp1d ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ ∧ m ∈ M + K … N + K → m ∈ ℤ
79 78 ex ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → m ∈ M + K … N + K → m ∈ ℤ
80 zcn ⊢ m ∈ ℤ → m ∈ ℂ
81 zcn ⊢ K ∈ ℤ → K ∈ ℂ
82 zcn ⊢ k ∈ ℤ → k ∈ ℂ
83 subadd ⊢ m ∈ ℂ ∧ K ∈ ℂ ∧ k ∈ ℂ → m − K = k ↔ K + k = m
84 eqcom ⊢ m − K = k ↔ k = m − K
85 eqcom ⊢ K + k = m ↔ m = K + k
86 83 84 85 3bitr3g ⊢ m ∈ ℂ ∧ K ∈ ℂ ∧ k ∈ ℂ → k = m − K ↔ m = K + k
87 addcom ⊢ K ∈ ℂ ∧ k ∈ ℂ → K + k = k + K
88 87 3adant1 ⊢ m ∈ ℂ ∧ K ∈ ℂ ∧ k ∈ ℂ → K + k = k + K
89 88 eqeq2d ⊢ m ∈ ℂ ∧ K ∈ ℂ ∧ k ∈ ℂ → m = K + k ↔ m = k + K
90 86 89 bitrd ⊢ m ∈ ℂ ∧ K ∈ ℂ ∧ k ∈ ℂ → k = m − K ↔ m = k + K
91 80 81 82 90 syl3an ⊢ m ∈ ℤ ∧ K ∈ ℤ ∧ k ∈ ℤ → k = m − K ↔ m = k + K
92 91 3coml ⊢ K ∈ ℤ ∧ k ∈ ℤ ∧ m ∈ ℤ → k = m − K ↔ m = k + K
93 92 3expib ⊢ K ∈ ℤ → k ∈ ℤ ∧ m ∈ ℤ → k = m − K ↔ m = k + K
94 93 3ad2ant3 ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ ℤ ∧ m ∈ ℤ → k = m − K ↔ m = k + K
95 76 79 94 syl2and ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → k ∈ M … N ∧ m ∈ M + K … N + K → k = m − K ↔ m = k + K
96 1 2 41 73 95 en3d ⊢ M ∈ ℤ ∧ N ∈ ℤ ∧ K ∈ ℤ → M … N ≈ M + K … N + K