Metamath Proof Explorer


Theorem gagrp

Description: The left argument of a group action is a group. (Contributed by Jeff Hankins, 11-Aug-2009) (Revised by Mario Carneiro, 30-Apr-2015)

Ref Expression
Assertion gagrp ⊢ ⊕ ˙ ∈ G GrpAct Y → G ∈ Grp

Proof

Step Hyp Ref Expression
1 eqid ⊢ Base G = Base G
2 eqid ⊢ + G = + G
3 eqid ⊢ 0 G = 0 G
4 1 2 3 isga ⊢ ⊕ ˙ ∈ G GrpAct Y ↔ G ∈ Grp ∧ Y ∈ V ∧ ⊕ ˙ : Base G × Y ⟶ Y ∧ ∀ x ∈ Y 0 G ⊕ ˙ x = x ∧ ∀ y ∈ Base G ∀ z ∈ Base G y + G z ⊕ ˙ x = y ⊕ ˙ z ⊕ ˙ x
5 4 simplbi ⊢ ⊕ ˙ ∈ G GrpAct Y → G ∈ Grp ∧ Y ∈ V
6 5 simpld ⊢ ⊕ ˙ ∈ G GrpAct Y → G ∈ Grp