Metamath Proof Explorer


Theorem gausslemma2dlem4

Description: Lemma 4 for gausslemma2d . (Contributed by AV, 16-Jun-2021)

Ref Expression
Hypotheses gausslemma2d.p ⊢ φ → P ∈ ℙ ∖ 2
gausslemma2d.h ⊢ H = P − 1 2
gausslemma2d.r ⊢ R = x ∈ 1 … H ⟼ if x ⋅ 2 < P 2 x ⋅ 2 P − x ⋅ 2
gausslemma2d.m ⊢ M = P 4
Assertion gausslemma2dlem4 ⊢ φ → H ! = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k

Proof

Step Hyp Ref Expression
1 gausslemma2d.p ⊢ φ → P ∈ ℙ ∖ 2
2 gausslemma2d.h ⊢ H = P − 1 2
3 gausslemma2d.r ⊢ R = x ∈ 1 … H ⟼ if x ⋅ 2 < P 2 x ⋅ 2 P − x ⋅ 2
4 gausslemma2d.m ⊢ M = P 4
5 1 2 3 gausslemma2dlem1 ⊢ φ → H ! = ∏ k = 1 H R ⁡ k
6 eldif ⊢ P ∈ ℙ ∖ 2 ↔ P ∈ ℙ ∧ ¬ P ∈ 2
7 prm23ge5 ⊢ P ∈ ℙ → P = 2 ∨ P = 3 ∨ P ∈ ℤ ≥ 5
8 eleq1 ⊢ P = 2 → P ∈ 2 ↔ 2 ∈ 2
9 8 notbid ⊢ P = 2 → ¬ P ∈ 2 ↔ ¬ 2 ∈ 2
10 2ex ⊢ 2 ∈ V
11 10 snid ⊢ 2 ∈ 2
12 11 2a1i ⊢ P = 2 → ∏ k = 1 H R ⁡ k ≠ ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k → 2 ∈ 2
13 12 necon1bd ⊢ P = 2 → ¬ 2 ∈ 2 → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
14 13 a1dd ⊢ P = 2 → ¬ 2 ∈ 2 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
15 9 14 sylbid ⊢ P = 2 → ¬ P ∈ 2 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
16 3lt4 ⊢ 3 < 4
17 breq1 ⊢ P = 3 → P < 4 ↔ 3 < 4
18 16 17 mpbiri ⊢ P = 3 → P < 4
19 3nn0 ⊢ 3 ∈ ℕ 0
20 eleq1 ⊢ P = 3 → P ∈ ℕ 0 ↔ 3 ∈ ℕ 0
21 19 20 mpbiri ⊢ P = 3 → P ∈ ℕ 0
22 4nn ⊢ 4 ∈ ℕ
23 divfl0 ⊢ P ∈ ℕ 0 ∧ 4 ∈ ℕ → P < 4 ↔ P 4 = 0
24 21 22 23 sylancl ⊢ P = 3 → P < 4 ↔ P 4 = 0
25 18 24 mpbid ⊢ P = 3 → P 4 = 0
26 4 25 eqtrid ⊢ P = 3 → M = 0
27 oveq2 ⊢ M = 0 → 1 … M = 1 … 0
28 27 adantr ⊢ M = 0 ∧ φ → 1 … M = 1 … 0
29 fz10 ⊢ 1 … 0 = ∅
30 28 29 eqtrdi ⊢ M = 0 ∧ φ → 1 … M = ∅
31 30 prodeq1d ⊢ M = 0 ∧ φ → ∏ k = 1 M R ⁡ k = ∏ k ∈ ∅ R ⁡ k
32 prod0 ⊢ ∏ k ∈ ∅ R ⁡ k = 1
33 31 32 eqtrdi ⊢ M = 0 ∧ φ → ∏ k = 1 M R ⁡ k = 1
34 oveq1 ⊢ M = 0 → M + 1 = 0 + 1
35 34 adantr ⊢ M = 0 ∧ φ → M + 1 = 0 + 1
36 0p1e1 ⊢ 0 + 1 = 1
37 35 36 eqtrdi ⊢ M = 0 ∧ φ → M + 1 = 1
38 37 oveq1d ⊢ M = 0 ∧ φ → M + 1 … H = 1 … H
39 38 prodeq1d ⊢ M = 0 ∧ φ → ∏ k = M + 1 H R ⁡ k = ∏ k = 1 H R ⁡ k
40 33 39 oveq12d ⊢ M = 0 ∧ φ → ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k = 1 ⁢ ∏ k = 1 H R ⁡ k
41 fzfid ⊢ M = 0 ∧ φ → 1 … H ∈ Fin
42 oveq1 ⊢ x = k → x ⋅ 2 = k ⋅ 2
43 42 breq1d ⊢ x = k → x ⋅ 2 < P 2 ↔ k ⋅ 2 < P 2
44 42 oveq2d ⊢ x = k → P − x ⋅ 2 = P − k ⋅ 2
45 43 42 44 ifbieq12d ⊢ x = k → if x ⋅ 2 < P 2 x ⋅ 2 P − x ⋅ 2 = if k ⋅ 2 < P 2 k ⋅ 2 P − k ⋅ 2
46 simpr ⊢ φ ∧ k ∈ 1 … H → k ∈ 1 … H
47 elfzelz ⊢ k ∈ 1 … H → k ∈ ℤ
48 47 zcnd ⊢ k ∈ 1 … H → k ∈ ℂ
49 2cnd ⊢ k ∈ 1 … H → 2 ∈ ℂ
50 48 49 mulcld ⊢ k ∈ 1 … H → k ⋅ 2 ∈ ℂ
51 50 adantl ⊢ φ ∧ k ∈ 1 … H → k ⋅ 2 ∈ ℂ
52 eldifi ⊢ P ∈ ℙ ∖ 2 → P ∈ ℙ
53 prmz ⊢ P ∈ ℙ → P ∈ ℤ
54 53 zcnd ⊢ P ∈ ℙ → P ∈ ℂ
55 1 52 54 3syl ⊢ φ → P ∈ ℂ
56 55 adantr ⊢ φ ∧ k ∈ 1 … H → P ∈ ℂ
57 56 51 subcld ⊢ φ ∧ k ∈ 1 … H → P − k ⋅ 2 ∈ ℂ
58 51 57 ifcld ⊢ φ ∧ k ∈ 1 … H → if k ⋅ 2 < P 2 k ⋅ 2 P − k ⋅ 2 ∈ ℂ
59 3 45 46 58 fvmptd3 ⊢ φ ∧ k ∈ 1 … H → R ⁡ k = if k ⋅ 2 < P 2 k ⋅ 2 P − k ⋅ 2
60 59 58 eqeltrd ⊢ φ ∧ k ∈ 1 … H → R ⁡ k ∈ ℂ
61 60 adantll ⊢ M = 0 ∧ φ ∧ k ∈ 1 … H → R ⁡ k ∈ ℂ
62 41 61 fprodcl ⊢ M = 0 ∧ φ → ∏ k = 1 H R ⁡ k ∈ ℂ
63 62 mullidd ⊢ M = 0 ∧ φ → 1 ⁢ ∏ k = 1 H R ⁡ k = ∏ k = 1 H R ⁡ k
64 40 63 eqtr2d ⊢ M = 0 ∧ φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
65 64 ex ⊢ M = 0 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
66 26 65 syl ⊢ P = 3 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
67 66 a1d ⊢ P = 3 → ¬ P ∈ 2 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
68 1 4 gausslemma2dlem0d ⊢ φ → M ∈ ℕ 0
69 68 nn0red ⊢ φ → M ∈ ℝ
70 69 ltp1d ⊢ φ → M < M + 1
71 fzdisj ⊢ M < M + 1 → 1 … M ∩ M + 1 … H = ∅
72 70 71 syl ⊢ φ → 1 … M ∩ M + 1 … H = ∅
73 72 adantl ⊢ P ∈ ℤ ≥ 5 ∧ φ → 1 … M ∩ M + 1 … H = ∅
74 eluzelre ⊢ P ∈ ℤ ≥ 5 → P ∈ ℝ
75 4re ⊢ 4 ∈ ℝ
76 75 a1i ⊢ P ∈ ℤ ≥ 5 → 4 ∈ ℝ
77 4ne0 ⊢ 4 ≠ 0
78 77 a1i ⊢ P ∈ ℤ ≥ 5 → 4 ≠ 0
79 74 76 78 redivcld ⊢ P ∈ ℤ ≥ 5 → P 4 ∈ ℝ
80 79 flcld ⊢ P ∈ ℤ ≥ 5 → P 4 ∈ ℤ
81 nnrp ⊢ 4 ∈ ℕ → 4 ∈ ℝ +
82 22 81 ax-mp ⊢ 4 ∈ ℝ +
83 eluz2 ⊢ P ∈ ℤ ≥ 5 ↔ 5 ∈ ℤ ∧ P ∈ ℤ ∧ 5 ≤ P
84 4lt5 ⊢ 4 < 5
85 5re ⊢ 5 ∈ ℝ
86 85 a1i ⊢ 5 ∈ ℤ ∧ P ∈ ℤ → 5 ∈ ℝ
87 zre ⊢ P ∈ ℤ → P ∈ ℝ
88 87 adantl ⊢ 5 ∈ ℤ ∧ P ∈ ℤ → P ∈ ℝ
89 ltleletr ⊢ 4 ∈ ℝ ∧ 5 ∈ ℝ ∧ P ∈ ℝ → 4 < 5 ∧ 5 ≤ P → 4 ≤ P
90 75 86 88 89 mp3an2i ⊢ 5 ∈ ℤ ∧ P ∈ ℤ → 4 < 5 ∧ 5 ≤ P → 4 ≤ P
91 84 90 mpani ⊢ 5 ∈ ℤ ∧ P ∈ ℤ → 5 ≤ P → 4 ≤ P
92 91 3impia ⊢ 5 ∈ ℤ ∧ P ∈ ℤ ∧ 5 ≤ P → 4 ≤ P
93 83 92 sylbi ⊢ P ∈ ℤ ≥ 5 → 4 ≤ P
94 divge1 ⊢ 4 ∈ ℝ + ∧ P ∈ ℝ ∧ 4 ≤ P → 1 ≤ P 4
95 82 74 93 94 mp3an2i ⊢ P ∈ ℤ ≥ 5 → 1 ≤ P 4
96 1zzd ⊢ P ∈ ℤ ≥ 5 → 1 ∈ ℤ
97 flge ⊢ P 4 ∈ ℝ ∧ 1 ∈ ℤ → 1 ≤ P 4 ↔ 1 ≤ P 4
98 79 96 97 syl2anc ⊢ P ∈ ℤ ≥ 5 → 1 ≤ P 4 ↔ 1 ≤ P 4
99 95 98 mpbid ⊢ P ∈ ℤ ≥ 5 → 1 ≤ P 4
100 elnnz1 ⊢ P 4 ∈ ℕ ↔ P 4 ∈ ℤ ∧ 1 ≤ P 4
101 80 99 100 sylanbrc ⊢ P ∈ ℤ ≥ 5 → P 4 ∈ ℕ
102 101 adantl ⊢ P ∈ ℙ ∖ 2 ∧ P ∈ ℤ ≥ 5 → P 4 ∈ ℕ
103 oddprm ⊢ P ∈ ℙ ∖ 2 → P − 1 2 ∈ ℕ
104 103 adantr ⊢ P ∈ ℙ ∖ 2 ∧ P ∈ ℤ ≥ 5 → P − 1 2 ∈ ℕ
105 prmuz2 ⊢ P ∈ ℙ → P ∈ ℤ ≥ 2
106 52 105 syl ⊢ P ∈ ℙ ∖ 2 → P ∈ ℤ ≥ 2
107 106 adantr ⊢ P ∈ ℙ ∖ 2 ∧ P ∈ ℤ ≥ 5 → P ∈ ℤ ≥ 2
108 fldiv4lem1div2uz2 ⊢ P ∈ ℤ ≥ 2 → P 4 ≤ P − 1 2
109 107 108 syl ⊢ P ∈ ℙ ∖ 2 ∧ P ∈ ℤ ≥ 5 → P 4 ≤ P − 1 2
110 102 104 109 3jca ⊢ P ∈ ℙ ∖ 2 ∧ P ∈ ℤ ≥ 5 → P 4 ∈ ℕ ∧ P − 1 2 ∈ ℕ ∧ P 4 ≤ P − 1 2
111 110 ex ⊢ P ∈ ℙ ∖ 2 → P ∈ ℤ ≥ 5 → P 4 ∈ ℕ ∧ P − 1 2 ∈ ℕ ∧ P 4 ≤ P − 1 2
112 1 111 syl ⊢ φ → P ∈ ℤ ≥ 5 → P 4 ∈ ℕ ∧ P − 1 2 ∈ ℕ ∧ P 4 ≤ P − 1 2
113 112 impcom ⊢ P ∈ ℤ ≥ 5 ∧ φ → P 4 ∈ ℕ ∧ P − 1 2 ∈ ℕ ∧ P 4 ≤ P − 1 2
114 2 oveq2i ⊢ 1 … H = 1 … P − 1 2
115 4 114 eleq12i ⊢ M ∈ 1 … H ↔ P 4 ∈ 1 … P − 1 2
116 elfz1b ⊢ P 4 ∈ 1 … P − 1 2 ↔ P 4 ∈ ℕ ∧ P − 1 2 ∈ ℕ ∧ P 4 ≤ P − 1 2
117 115 116 bitri ⊢ M ∈ 1 … H ↔ P 4 ∈ ℕ ∧ P − 1 2 ∈ ℕ ∧ P 4 ≤ P − 1 2
118 113 117 sylibr ⊢ P ∈ ℤ ≥ 5 ∧ φ → M ∈ 1 … H
119 fzsplit ⊢ M ∈ 1 … H → 1 … H = 1 … M ∪ M + 1 … H
120 118 119 syl ⊢ P ∈ ℤ ≥ 5 ∧ φ → 1 … H = 1 … M ∪ M + 1 … H
121 fzfid ⊢ P ∈ ℤ ≥ 5 ∧ φ → 1 … H ∈ Fin
122 60 adantll ⊢ P ∈ ℤ ≥ 5 ∧ φ ∧ k ∈ 1 … H → R ⁡ k ∈ ℂ
123 73 120 121 122 fprodsplit ⊢ P ∈ ℤ ≥ 5 ∧ φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
124 123 ex ⊢ P ∈ ℤ ≥ 5 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
125 124 a1d ⊢ P ∈ ℤ ≥ 5 → ¬ P ∈ 2 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
126 15 67 125 3jaoi ⊢ P = 2 ∨ P = 3 ∨ P ∈ ℤ ≥ 5 → ¬ P ∈ 2 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
127 7 126 syl ⊢ P ∈ ℙ → ¬ P ∈ 2 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
128 127 imp ⊢ P ∈ ℙ ∧ ¬ P ∈ 2 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
129 6 128 sylbi ⊢ P ∈ ℙ ∖ 2 → φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
130 1 129 mpcom ⊢ φ → ∏ k = 1 H R ⁡ k = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k
131 5 130 eqtrd ⊢ φ → H ! = ∏ k = 1 M R ⁡ k ⁢ ∏ k = M + 1 H R ⁡ k