Metamath Proof Explorer


Theorem gboge9

Description: Any odd Goldbach number is greater than or equal to 9. Because of 9gbo , this bound is strict. (Contributed by AV, 26-Jul-2020)

Ref Expression
Assertion gboge9 ⊢ Z ∈ GoldbachOdd → 9 ≤ Z

Proof

Step Hyp Ref Expression
1 isgbo ⊢ Z ∈ GoldbachOdd ↔ Z ∈ Odd ∧ ∃ p ∈ ℙ ∃ q ∈ ℙ ∃ r ∈ ℙ p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd ∧ Z = p + q + r
2 df-3an ⊢ p ∈ ℙ ∧ q ∈ ℙ ∧ r ∈ ℙ ↔ p ∈ ℙ ∧ q ∈ ℙ ∧ r ∈ ℙ
3 an6 ⊢ p ∈ ℙ ∧ q ∈ ℙ ∧ r ∈ ℙ ∧ p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd ↔ p ∈ ℙ ∧ p ∈ Odd ∧ q ∈ ℙ ∧ q ∈ Odd ∧ r ∈ ℙ ∧ r ∈ Odd
4 oddprmuzge3 ⊢ p ∈ ℙ ∧ p ∈ Odd → p ∈ ℤ ≥ 3
5 oddprmuzge3 ⊢ q ∈ ℙ ∧ q ∈ Odd → q ∈ ℤ ≥ 3
6 oddprmuzge3 ⊢ r ∈ ℙ ∧ r ∈ Odd → r ∈ ℤ ≥ 3
7 6p3e9 ⊢ 6 + 3 = 9
8 eluzelz ⊢ p ∈ ℤ ≥ 3 → p ∈ ℤ
9 eluzelz ⊢ q ∈ ℤ ≥ 3 → q ∈ ℤ
10 zaddcl ⊢ p ∈ ℤ ∧ q ∈ ℤ → p + q ∈ ℤ
11 8 9 10 syl2an ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 → p + q ∈ ℤ
12 11 zred ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 → p + q ∈ ℝ
13 eluzelre ⊢ r ∈ ℤ ≥ 3 → r ∈ ℝ
14 12 13 anim12i ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 ∧ r ∈ ℤ ≥ 3 → p + q ∈ ℝ ∧ r ∈ ℝ
15 14 3impa ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 ∧ r ∈ ℤ ≥ 3 → p + q ∈ ℝ ∧ r ∈ ℝ
16 6re ⊢ 6 ∈ ℝ
17 3re ⊢ 3 ∈ ℝ
18 16 17 pm3.2i ⊢ 6 ∈ ℝ ∧ 3 ∈ ℝ
19 15 18 jctil ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 ∧ r ∈ ℤ ≥ 3 → 6 ∈ ℝ ∧ 3 ∈ ℝ ∧ p + q ∈ ℝ ∧ r ∈ ℝ
20 3p3e6 ⊢ 3 + 3 = 6
21 eluzelre ⊢ p ∈ ℤ ≥ 3 → p ∈ ℝ
22 eluzelre ⊢ q ∈ ℤ ≥ 3 → q ∈ ℝ
23 21 22 anim12i ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 → p ∈ ℝ ∧ q ∈ ℝ
24 17 17 pm3.2i ⊢ 3 ∈ ℝ ∧ 3 ∈ ℝ
25 23 24 jctil ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 → 3 ∈ ℝ ∧ 3 ∈ ℝ ∧ p ∈ ℝ ∧ q ∈ ℝ
26 eluzle ⊢ p ∈ ℤ ≥ 3 → 3 ≤ p
27 eluzle ⊢ q ∈ ℤ ≥ 3 → 3 ≤ q
28 26 27 anim12i ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 → 3 ≤ p ∧ 3 ≤ q
29 le2add ⊢ 3 ∈ ℝ ∧ 3 ∈ ℝ ∧ p ∈ ℝ ∧ q ∈ ℝ → 3 ≤ p ∧ 3 ≤ q → 3 + 3 ≤ p + q
30 25 28 29 sylc ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 → 3 + 3 ≤ p + q
31 20 30 eqbrtrrid ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 → 6 ≤ p + q
32 31 3adant3 ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 ∧ r ∈ ℤ ≥ 3 → 6 ≤ p + q
33 eluzle ⊢ r ∈ ℤ ≥ 3 → 3 ≤ r
34 33 3ad2ant3 ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 ∧ r ∈ ℤ ≥ 3 → 3 ≤ r
35 32 34 jca ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 ∧ r ∈ ℤ ≥ 3 → 6 ≤ p + q ∧ 3 ≤ r
36 le2add ⊢ 6 ∈ ℝ ∧ 3 ∈ ℝ ∧ p + q ∈ ℝ ∧ r ∈ ℝ → 6 ≤ p + q ∧ 3 ≤ r → 6 + 3 ≤ p + q + r
37 19 35 36 sylc ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 ∧ r ∈ ℤ ≥ 3 → 6 + 3 ≤ p + q + r
38 7 37 eqbrtrrid ⊢ p ∈ ℤ ≥ 3 ∧ q ∈ ℤ ≥ 3 ∧ r ∈ ℤ ≥ 3 → 9 ≤ p + q + r
39 4 5 6 38 syl3an ⊢ p ∈ ℙ ∧ p ∈ Odd ∧ q ∈ ℙ ∧ q ∈ Odd ∧ r ∈ ℙ ∧ r ∈ Odd → 9 ≤ p + q + r
40 3 39 sylbi ⊢ p ∈ ℙ ∧ q ∈ ℙ ∧ r ∈ ℙ ∧ p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd → 9 ≤ p + q + r
41 2 40 sylanbr ⊢ p ∈ ℙ ∧ q ∈ ℙ ∧ r ∈ ℙ ∧ p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd → 9 ≤ p + q + r
42 breq2 ⊢ Z = p + q + r → 9 ≤ Z ↔ 9 ≤ p + q + r
43 41 42 syl5ibrcom ⊢ p ∈ ℙ ∧ q ∈ ℙ ∧ r ∈ ℙ ∧ p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd → Z = p + q + r → 9 ≤ Z
44 43 expimpd ⊢ p ∈ ℙ ∧ q ∈ ℙ ∧ r ∈ ℙ → p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd ∧ Z = p + q + r → 9 ≤ Z
45 44 rexlimdva ⊢ p ∈ ℙ ∧ q ∈ ℙ → ∃ r ∈ ℙ p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd ∧ Z = p + q + r → 9 ≤ Z
46 45 a1i ⊢ Z ∈ Odd → p ∈ ℙ ∧ q ∈ ℙ → ∃ r ∈ ℙ p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd ∧ Z = p + q + r → 9 ≤ Z
47 46 rexlimdvv ⊢ Z ∈ Odd → ∃ p ∈ ℙ ∃ q ∈ ℙ ∃ r ∈ ℙ p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd ∧ Z = p + q + r → 9 ≤ Z
48 47 imp ⊢ Z ∈ Odd ∧ ∃ p ∈ ℙ ∃ q ∈ ℙ ∃ r ∈ ℙ p ∈ Odd ∧ q ∈ Odd ∧ r ∈ Odd ∧ Z = p + q + r → 9 ≤ Z
49 1 48 sylbi ⊢ Z ∈ GoldbachOdd → 9 ≤ Z