Metamath Proof Explorer


Theorem gicrcl

Description: Isomorphism implies the right side is a group. (Contributed by Mario Carneiro, 6-May-2015)

Ref Expression
Assertion gicrcl ⊢ R ≃ 𝑔 S → S ∈ Grp

Proof

Step Hyp Ref Expression
1 brgic ⊢ R ≃ 𝑔 S ↔ R GrpIso S ≠ ∅
2 n0 ⊢ R GrpIso S ≠ ∅ ↔ ∃ f f ∈ R GrpIso S
3 1 2 bitri ⊢ R ≃ 𝑔 S ↔ ∃ f f ∈ R GrpIso S
4 gimghm ⊢ f ∈ R GrpIso S → f ∈ R GrpHom S
5 ghmgrp2 ⊢ f ∈ R GrpHom S → S ∈ Grp
6 4 5 syl ⊢ f ∈ R GrpIso S → S ∈ Grp
7 6 exlimiv ⊢ ∃ f f ∈ R GrpIso S → S ∈ Grp
8 3 7 sylbi ⊢ R ≃ 𝑔 S → S ∈ Grp