Metamath Proof Explorer


Theorem gicsym

Description: Isomorphism is symmetric. (Contributed by Mario Carneiro, 21-Apr-2016)

Ref Expression
Assertion gicsym ⊢ R ≃ 𝑔 S → S ≃ 𝑔 R

Proof

Step Hyp Ref Expression
1 brgic ⊢ R ≃ 𝑔 S ↔ R GrpIso S ≠ ∅
2 n0 ⊢ R GrpIso S ≠ ∅ ↔ ∃ f f ∈ R GrpIso S
3 gimcnv ⊢ f ∈ R GrpIso S → f -1 ∈ S GrpIso R
4 brgici ⊢ f -1 ∈ S GrpIso R → S ≃ 𝑔 R
5 3 4 syl ⊢ f ∈ R GrpIso S → S ≃ 𝑔 R
6 5 exlimiv ⊢ ∃ f f ∈ R GrpIso S → S ≃ 𝑔 R
7 2 6 sylbi ⊢ R GrpIso S ≠ ∅ → S ≃ 𝑔 R
8 1 7 sylbi ⊢ R ≃ 𝑔 S → S ≃ 𝑔 R