Metamath Proof Explorer


Theorem gimghm

Description: An isomorphism of groups is a homomorphism. (Contributed by Stefan O'Rear, 21-Jan-2015) (Revised by Mario Carneiro, 6-May-2015)

Ref Expression
Assertion gimghm ⊢ F ∈ R GrpIso S → F ∈ R GrpHom S

Proof

Step Hyp Ref Expression
1 eqid ⊢ Base R = Base R
2 eqid ⊢ Base S = Base S
3 1 2 isgim ⊢ F ∈ R GrpIso S ↔ F ∈ R GrpHom S ∧ F : Base R ⟶ 1-1 onto Base S
4 3 simplbi ⊢ F ∈ R GrpIso S → F ∈ R GrpHom S