Metamath Proof Explorer


Theorem grpinvcld

Description: A group element's inverse is a group element. (Contributed by SN, 29-Jan-2025)

Ref Expression
Hypotheses grpinvcld.b ⊢ B = Base G
grpinvcld.n ⊢ N = inv g ⁡ G
grpinvcld.g ⊢ φ → G ∈ Grp
grpinvcld.1 ⊢ φ → X ∈ B
Assertion grpinvcld ⊢ φ → N ⁡ X ∈ B

Proof

Step Hyp Ref Expression
1 grpinvcld.b ⊢ B = Base G
2 grpinvcld.n ⊢ N = inv g ⁡ G
3 grpinvcld.g ⊢ φ → G ∈ Grp
4 grpinvcld.1 ⊢ φ → X ∈ B
5 1 2 grpinvcl ⊢ G ∈ Grp ∧ X ∈ B → N ⁡ X ∈ B
6 3 4 5 syl2anc ⊢ φ → N ⁡ X ∈ B