Metamath Proof Explorer


Theorem grpinvex

Description: Every member of a group has a left inverse. (Contributed by NM, 16-Aug-2011) (Revised by Mario Carneiro, 6-Jan-2015)

Ref Expression
Hypotheses grpcl.b ⊢ B = Base G
grpcl.p ⊢ + ˙ = + G
grpinvex.p ⊢ 0 ˙ = 0 G
Assertion grpinvex ⊢ G ∈ Grp ∧ X ∈ B → ∃ y ∈ B y + ˙ X = 0 ˙

Proof

Step Hyp Ref Expression
1 grpcl.b ⊢ B = Base G
2 grpcl.p ⊢ + ˙ = + G
3 grpinvex.p ⊢ 0 ˙ = 0 G
4 1 2 3 isgrp ⊢ G ∈ Grp ↔ G ∈ Mnd ∧ ∀ x ∈ B ∃ y ∈ B y + ˙ x = 0 ˙
5 4 simprbi ⊢ G ∈ Grp → ∀ x ∈ B ∃ y ∈ B y + ˙ x = 0 ˙
6 oveq2 ⊢ x = X → y + ˙ x = y + ˙ X
7 6 eqeq1d ⊢ x = X → y + ˙ x = 0 ˙ ↔ y + ˙ X = 0 ˙
8 7 rexbidv ⊢ x = X → ∃ y ∈ B y + ˙ x = 0 ˙ ↔ ∃ y ∈ B y + ˙ X = 0 ˙
9 8 rspccva ⊢ ∀ x ∈ B ∃ y ∈ B y + ˙ x = 0 ˙ ∧ X ∈ B → ∃ y ∈ B y + ˙ X = 0 ˙
10 5 9 sylan ⊢ G ∈ Grp ∧ X ∈ B → ∃ y ∈ B y + ˙ X = 0 ˙