Metamath Proof Explorer


Theorem grpmnd

Description: A group is a monoid. (Contributed by Mario Carneiro, 6-Jan-2015)

Ref Expression
Assertion grpmnd ⊢ G ∈ Grp → G ∈ Mnd

Proof

Step Hyp Ref Expression
1 eqid ⊢ Base G = Base G
2 eqid ⊢ + G = + G
3 eqid ⊢ 0 G = 0 G
4 1 2 3 isgrp ⊢ G ∈ Grp ↔ G ∈ Mnd ∧ ∀ a ∈ Base G ∃ m ∈ Base G m + G a = 0 G
5 4 simplbi ⊢ G ∈ Grp → G ∈ Mnd