Metamath Proof Explorer


Theorem grprinv

Description: The right inverse of a group element. (Contributed by NM, 24-Aug-2011) (Revised by Mario Carneiro, 6-Jan-2015)

Ref Expression
Hypotheses grpinv.b ⊢ B = Base G
grpinv.p ⊢ + ˙ = + G
grpinv.u ⊢ 0 ˙ = 0 G
grpinv.n ⊢ N = inv g ⁡ G
Assertion grprinv ⊢ G ∈ Grp ∧ X ∈ B → X + ˙ N ⁡ X = 0 ˙

Proof

Step Hyp Ref Expression
1 grpinv.b ⊢ B = Base G
2 grpinv.p ⊢ + ˙ = + G
3 grpinv.u ⊢ 0 ˙ = 0 G
4 grpinv.n ⊢ N = inv g ⁡ G
5 1 2 grpcl ⊢ G ∈ Grp ∧ x ∈ B ∧ y ∈ B → x + ˙ y ∈ B
6 1 3 grpidcl ⊢ G ∈ Grp → 0 ˙ ∈ B
7 1 2 3 grplid ⊢ G ∈ Grp ∧ x ∈ B → 0 ˙ + ˙ x = x
8 1 2 grpass ⊢ G ∈ Grp ∧ x ∈ B ∧ y ∈ B ∧ z ∈ B → x + ˙ y + ˙ z = x + ˙ y + ˙ z
9 1 2 3 grpinvex ⊢ G ∈ Grp ∧ x ∈ B → ∃ y ∈ B y + ˙ x = 0 ˙
10 simpr ⊢ G ∈ Grp ∧ X ∈ B → X ∈ B
11 1 4 grpinvcl ⊢ G ∈ Grp ∧ X ∈ B → N ⁡ X ∈ B
12 1 2 3 4 grplinv ⊢ G ∈ Grp ∧ X ∈ B → N ⁡ X + ˙ X = 0 ˙
13 5 6 7 8 9 10 11 12 grpinva ⊢ G ∈ Grp ∧ X ∈ B → X + ˙ N ⁡ X = 0 ˙