Metamath Proof Explorer


Theorem grpsubfvalALT

Description: Shorter proof of grpsubfval using ax-rep . (Contributed by NM, 31-Mar-2014) (Revised by Stefan O'Rear, 27-Mar-2015) (Proof shortened by AV, 19-Feb-2024) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypotheses grpsubval.b ⊢ B = Base G
grpsubval.p ⊢ + ˙ = + G
grpsubval.i ⊢ I = inv g ⁡ G
grpsubval.m ⊢ - ˙ = - G
Assertion grpsubfvalALT ⊢ - ˙ = x ∈ B , y ∈ B ⟼ x + ˙ I ⁡ y

Proof

Step Hyp Ref Expression
1 grpsubval.b ⊢ B = Base G
2 grpsubval.p ⊢ + ˙ = + G
3 grpsubval.i ⊢ I = inv g ⁡ G
4 grpsubval.m ⊢ - ˙ = - G
5 fveq2 ⊢ g = G → Base g = Base G
6 5 1 eqtr4di ⊢ g = G → Base g = B
7 fveq2 ⊢ g = G → + g = + G
8 7 2 eqtr4di ⊢ g = G → + g = + ˙
9 eqidd ⊢ g = G → x = x
10 fveq2 ⊢ g = G → inv g ⁡ g = inv g ⁡ G
11 10 3 eqtr4di ⊢ g = G → inv g ⁡ g = I
12 11 fveq1d ⊢ g = G → inv g ⁡ g ⁡ y = I ⁡ y
13 8 9 12 oveq123d ⊢ g = G → x + g inv g ⁡ g ⁡ y = x + ˙ I ⁡ y
14 6 6 13 mpoeq123dv ⊢ g = G → x ∈ Base g , y ∈ Base g ⟼ x + g inv g ⁡ g ⁡ y = x ∈ B , y ∈ B ⟼ x + ˙ I ⁡ y
15 df-sbg ⊢ - 𝑔 = g ∈ V ⟼ x ∈ Base g , y ∈ Base g ⟼ x + g inv g ⁡ g ⁡ y
16 1 fvexi ⊢ B ∈ V
17 16 16 mpoex ⊢ x ∈ B , y ∈ B ⟼ x + ˙ I ⁡ y ∈ V
18 14 15 17 fvmpt ⊢ G ∈ V → - G = x ∈ B , y ∈ B ⟼ x + ˙ I ⁡ y
19 4 18 eqtrid ⊢ G ∈ V → - ˙ = x ∈ B , y ∈ B ⟼ x + ˙ I ⁡ y
20 fvprc ⊢ ¬ G ∈ V → - G = ∅
21 4 20 eqtrid ⊢ ¬ G ∈ V → - ˙ = ∅
22 fvprc ⊢ ¬ G ∈ V → Base G = ∅
23 1 22 eqtrid ⊢ ¬ G ∈ V → B = ∅
24 23 olcd ⊢ ¬ G ∈ V → B = ∅ ∨ B = ∅
25 0mpo0 ⊢ B = ∅ ∨ B = ∅ → x ∈ B , y ∈ B ⟼ x + ˙ I ⁡ y = ∅
26 24 25 syl ⊢ ¬ G ∈ V → x ∈ B , y ∈ B ⟼ x + ˙ I ⁡ y = ∅
27 21 26 eqtr4d ⊢ ¬ G ∈ V → - ˙ = x ∈ B , y ∈ B ⟼ x + ˙ I ⁡ y
28 19 27 pm2.61i ⊢ - ˙ = x ∈ B , y ∈ B ⟼ x + ˙ I ⁡ y