Metamath Proof Explorer


Theorem harmoniclbnd

Description: A bound on the harmonic series, as compared to the natural logarithm. (Contributed by Mario Carneiro, 13-Apr-2016)

Ref Expression
Assertion harmoniclbnd ⊢ A ∈ ℝ + → log ⁡ A ≤ ∑ m = 1 A 1 m

Proof

Step Hyp Ref Expression
1 relogcl ⊢ A ∈ ℝ + → log ⁡ A ∈ ℝ
2 rprege0 ⊢ A ∈ ℝ + → A ∈ ℝ ∧ 0 ≤ A
3 flge0nn0 ⊢ A ∈ ℝ ∧ 0 ≤ A → A ∈ ℕ 0
4 2 3 syl ⊢ A ∈ ℝ + → A ∈ ℕ 0
5 nn0p1nn ⊢ A ∈ ℕ 0 → A + 1 ∈ ℕ
6 4 5 syl ⊢ A ∈ ℝ + → A + 1 ∈ ℕ
7 6 nnrpd ⊢ A ∈ ℝ + → A + 1 ∈ ℝ +
8 relogcl ⊢ A + 1 ∈ ℝ + → log ⁡ A + 1 ∈ ℝ
9 7 8 syl ⊢ A ∈ ℝ + → log ⁡ A + 1 ∈ ℝ
10 fzfid ⊢ A ∈ ℝ + → 1 … A ∈ Fin
11 elfznn ⊢ m ∈ 1 … A → m ∈ ℕ
12 11 adantl ⊢ A ∈ ℝ + ∧ m ∈ 1 … A → m ∈ ℕ
13 12 nnrecred ⊢ A ∈ ℝ + ∧ m ∈ 1 … A → 1 m ∈ ℝ
14 10 13 fsumrecl ⊢ A ∈ ℝ + → ∑ m = 1 A 1 m ∈ ℝ
15 rpre ⊢ A ∈ ℝ + → A ∈ ℝ
16 fllep1 ⊢ A ∈ ℝ → A ≤ A + 1
17 15 16 syl ⊢ A ∈ ℝ + → A ≤ A + 1
18 id ⊢ A ∈ ℝ + → A ∈ ℝ +
19 18 7 logled ⊢ A ∈ ℝ + → A ≤ A + 1 ↔ log ⁡ A ≤ log ⁡ A + 1
20 17 19 mpbid ⊢ A ∈ ℝ + → log ⁡ A ≤ log ⁡ A + 1
21 harmonicbnd3 ⊢ A ∈ ℕ 0 → ∑ m = 1 A 1 m − log ⁡ A + 1 ∈ 0 γ
22 4 21 syl ⊢ A ∈ ℝ + → ∑ m = 1 A 1 m − log ⁡ A + 1 ∈ 0 γ
23 0re ⊢ 0 ∈ ℝ
24 emre ⊢ γ ∈ ℝ
25 23 24 elicc2i ⊢ ∑ m = 1 A 1 m − log ⁡ A + 1 ∈ 0 γ ↔ ∑ m = 1 A 1 m − log ⁡ A + 1 ∈ ℝ ∧ 0 ≤ ∑ m = 1 A 1 m − log ⁡ A + 1 ∧ ∑ m = 1 A 1 m − log ⁡ A + 1 ≤ γ
26 25 simp2bi ⊢ ∑ m = 1 A 1 m − log ⁡ A + 1 ∈ 0 γ → 0 ≤ ∑ m = 1 A 1 m − log ⁡ A + 1
27 22 26 syl ⊢ A ∈ ℝ + → 0 ≤ ∑ m = 1 A 1 m − log ⁡ A + 1
28 14 9 subge0d ⊢ A ∈ ℝ + → 0 ≤ ∑ m = 1 A 1 m − log ⁡ A + 1 ↔ log ⁡ A + 1 ≤ ∑ m = 1 A 1 m
29 27 28 mpbid ⊢ A ∈ ℝ + → log ⁡ A + 1 ≤ ∑ m = 1 A 1 m
30 1 9 14 20 29 letrd ⊢ A ∈ ℝ + → log ⁡ A ≤ ∑ m = 1 A 1 m