Metamath Proof Explorer


Theorem hban

Description: If x is not free in ph and ps , it is not free in ( ph /\ ps ) . (Contributed by NM, 14-May-1993) (Proof shortened by Wolf Lammen, 2-Jan-2018) Reduce axiom dependencies. (Revised by SN and Sky Winter, 22-Oct-2026)

Ref Expression
Hypotheses hb.1 ⊢ φ → ∀ x φ
hb.2 ⊢ ψ → ∀ x ψ
Assertion hban ⊢ φ ∧ ψ → ∀ x φ ∧ ψ

Proof

Step Hyp Ref Expression
1 hb.1 ⊢ φ → ∀ x φ
2 hb.2 ⊢ ψ → ∀ x ψ
3 pm3.2 ⊢ φ → ψ → φ ∧ ψ
4 1 2 3 alrimdh ⊢ φ → ψ → ∀ x φ ∧ ψ
5 4 imp ⊢ φ ∧ ψ → ∀ x φ ∧ ψ