Metamath Proof Explorer


Theorem hdmapsub

Description: Part of proof of part 12 in Baer p. 49 line 5, (a-b)S = aS-bS in their notation (S = sigma). (Contributed by NM, 26-May-2015)

Ref Expression
Hypotheses hdmap12c.h ⊢ H = LHyp ⁡ K
hdmap12c.u ⊢ U = DVecH ⁡ K ⁡ W
hdmap12c.v ⊢ V = Base U
hdmap12c.m ⊢ - ˙ = - U
hdmap12c.c ⊢ C = LCDual ⁡ K ⁡ W
hdmap12c.n ⊢ N = - C
hdmap12c.s ⊢ S = HDMap ⁡ K ⁡ W
hdmap12c.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmap12c.x ⊢ φ → X ∈ V
hdmap12c.y ⊢ φ → Y ∈ V
Assertion hdmapsub ⊢ φ → S ⁡ X - ˙ Y = S ⁡ X N S ⁡ Y

Proof

Step Hyp Ref Expression
1 hdmap12c.h ⊢ H = LHyp ⁡ K
2 hdmap12c.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmap12c.v ⊢ V = Base U
4 hdmap12c.m ⊢ - ˙ = - U
5 hdmap12c.c ⊢ C = LCDual ⁡ K ⁡ W
6 hdmap12c.n ⊢ N = - C
7 hdmap12c.s ⊢ S = HDMap ⁡ K ⁡ W
8 hdmap12c.k ⊢ φ → K ∈ HL ∧ W ∈ H
9 hdmap12c.x ⊢ φ → X ∈ V
10 hdmap12c.y ⊢ φ → Y ∈ V
11 eqid ⊢ + U = + U
12 eqid ⊢ inv g ⁡ U = inv g ⁡ U
13 3 11 12 4 grpsubval ⊢ X ∈ V ∧ Y ∈ V → X - ˙ Y = X + U inv g ⁡ U ⁡ Y
14 9 10 13 syl2anc ⊢ φ → X - ˙ Y = X + U inv g ⁡ U ⁡ Y
15 14 fveq2d ⊢ φ → S ⁡ X - ˙ Y = S ⁡ X + U inv g ⁡ U ⁡ Y
16 eqid ⊢ + C = + C
17 1 2 8 dvhlmod ⊢ φ → U ∈ LMod
18 3 12 lmodvnegcl ⊢ U ∈ LMod ∧ Y ∈ V → inv g ⁡ U ⁡ Y ∈ V
19 17 10 18 syl2anc ⊢ φ → inv g ⁡ U ⁡ Y ∈ V
20 1 2 3 11 5 16 7 8 9 19 hdmapadd ⊢ φ → S ⁡ X + U inv g ⁡ U ⁡ Y = S ⁡ X + C S ⁡ inv g ⁡ U ⁡ Y
21 eqid ⊢ inv g ⁡ C = inv g ⁡ C
22 1 2 3 12 5 21 7 8 10 hdmapneg ⊢ φ → S ⁡ inv g ⁡ U ⁡ Y = inv g ⁡ C ⁡ S ⁡ Y
23 22 oveq2d ⊢ φ → S ⁡ X + C S ⁡ inv g ⁡ U ⁡ Y = S ⁡ X + C inv g ⁡ C ⁡ S ⁡ Y
24 15 20 23 3eqtrd ⊢ φ → S ⁡ X - ˙ Y = S ⁡ X + C inv g ⁡ C ⁡ S ⁡ Y
25 eqid ⊢ Base C = Base C
26 1 2 3 5 25 7 8 9 hdmapcl ⊢ φ → S ⁡ X ∈ Base C
27 1 2 3 5 25 7 8 10 hdmapcl ⊢ φ → S ⁡ Y ∈ Base C
28 25 16 21 6 grpsubval ⊢ S ⁡ X ∈ Base C ∧ S ⁡ Y ∈ Base C → S ⁡ X N S ⁡ Y = S ⁡ X + C inv g ⁡ C ⁡ S ⁡ Y
29 26 27 28 syl2anc ⊢ φ → S ⁡ X N S ⁡ Y = S ⁡ X + C inv g ⁡ C ⁡ S ⁡ Y
30 24 29 eqtr4d ⊢ φ → S ⁡ X - ˙ Y = S ⁡ X N S ⁡ Y