Metamath Proof Explorer


Theorem hlatexch3N

Description: Rearrange join of atoms in an equality. (Contributed by NM, 29-Jul-2013) (New usage is discouraged.)

Ref Expression
Hypotheses hlatexch4.j ⊢ ∨ ˙ = join ⁡ K
hlatexch4.a ⊢ A = Atoms ⁡ K
Assertion hlatexch3N ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → P ∨ ˙ Q = Q ∨ ˙ R

Proof

Step Hyp Ref Expression
1 hlatexch4.j ⊢ ∨ ˙ = join ⁡ K
2 hlatexch4.a ⊢ A = Atoms ⁡ K
3 simp1 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → K ∈ HL
4 simp21 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → P ∈ A
5 simp22 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → Q ∈ A
6 eqid ⊢ ≤ K = ≤ K
7 6 1 2 hlatlej2 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A → Q ≤ K P ∨ ˙ Q
8 3 4 5 7 syl3anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → Q ≤ K P ∨ ˙ Q
9 simp23 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → R ∈ A
10 6 1 2 hlatlej2 ⊢ K ∈ HL ∧ P ∈ A ∧ R ∈ A → R ≤ K P ∨ ˙ R
11 3 4 9 10 syl3anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → R ≤ K P ∨ ˙ R
12 simp3r ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → P ∨ ˙ Q = P ∨ ˙ R
13 11 12 breqtrrd ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → R ≤ K P ∨ ˙ Q
14 hllat ⊢ K ∈ HL → K ∈ Lat
15 14 3ad2ant1 ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → K ∈ Lat
16 eqid ⊢ Base K = Base K
17 16 2 atbase ⊢ Q ∈ A → Q ∈ Base K
18 5 17 syl ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → Q ∈ Base K
19 16 2 atbase ⊢ R ∈ A → R ∈ Base K
20 9 19 syl ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → R ∈ Base K
21 16 1 2 hlatjcl ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A → P ∨ ˙ Q ∈ Base K
22 3 4 5 21 syl3anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → P ∨ ˙ Q ∈ Base K
23 16 6 1 latjle12 ⊢ K ∈ Lat ∧ Q ∈ Base K ∧ R ∈ Base K ∧ P ∨ ˙ Q ∈ Base K → Q ≤ K P ∨ ˙ Q ∧ R ≤ K P ∨ ˙ Q ↔ Q ∨ ˙ R ≤ K P ∨ ˙ Q
24 15 18 20 22 23 syl13anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → Q ≤ K P ∨ ˙ Q ∧ R ≤ K P ∨ ˙ Q ↔ Q ∨ ˙ R ≤ K P ∨ ˙ Q
25 8 13 24 mpbi2and ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → Q ∨ ˙ R ≤ K P ∨ ˙ Q
26 simp3l ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → Q ≠ R
27 6 1 2 ps-1 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∈ A ∧ Q ∈ A → Q ∨ ˙ R ≤ K P ∨ ˙ Q ↔ Q ∨ ˙ R = P ∨ ˙ Q
28 3 5 9 26 4 5 27 syl132anc ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → Q ∨ ˙ R ≤ K P ∨ ˙ Q ↔ Q ∨ ˙ R = P ∨ ˙ Q
29 25 28 mpbid ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → Q ∨ ˙ R = P ∨ ˙ Q
30 29 eqcomd ⊢ K ∈ HL ∧ P ∈ A ∧ Q ∈ A ∧ R ∈ A ∧ Q ≠ R ∧ P ∨ ˙ Q = P ∨ ˙ R → P ∨ ˙ Q = Q ∨ ˙ R