Metamath Proof Explorer


Theorem hlcgreq

Description: A constructed point on a half-line, at a given distance of its origin, (see hlcgrex ) is unique. Theorem 6.11 of Schwabhauser p. 44. (Contributed by Thierry Arnoux, 9-Aug-2020)

Ref Expression
Hypotheses hlcgreq.p ⊢ P = Base G
hlcgreq.i ⊢ - ˙ = dist ⁡ G
hlcgreq.k ⊢ K = hl 𝒢 ⁡ G
hlcgreq.a ⊢ φ → A ∈ P
hlcgreq.b ⊢ φ → B ∈ P
hlcgreq.c ⊢ φ → C ∈ P
hlcgreq.g ⊢ φ → G ∈ 𝒢 Tarski
hlcgreq.d ⊢ φ → D ∈ P
hlcgreq.1 ⊢ φ → D ≠ A
hlcgreq.2 ⊢ φ → B ≠ C
hlcgreq.3 ⊢ φ → X K ⁡ A D
hlcgreq.4 ⊢ φ → Y K ⁡ A D
hlcgreq.5 ⊢ φ → A - ˙ X = B - ˙ C
hlcgreq.6 ⊢ φ → A - ˙ Y = B - ˙ C
Assertion hlcgreq ⊢ φ → X = Y

Proof

Step Hyp Ref Expression
1 hlcgreq.p ⊢ P = Base G
2 hlcgreq.i ⊢ - ˙ = dist ⁡ G
3 hlcgreq.k ⊢ K = hl 𝒢 ⁡ G
4 hlcgreq.a ⊢ φ → A ∈ P
5 hlcgreq.b ⊢ φ → B ∈ P
6 hlcgreq.c ⊢ φ → C ∈ P
7 hlcgreq.g ⊢ φ → G ∈ 𝒢 Tarski
8 hlcgreq.d ⊢ φ → D ∈ P
9 hlcgreq.1 ⊢ φ → D ≠ A
10 hlcgreq.2 ⊢ φ → B ≠ C
11 hlcgreq.3 ⊢ φ → X K ⁡ A D
12 hlcgreq.4 ⊢ φ → Y K ⁡ A D
13 hlcgreq.5 ⊢ φ → A - ˙ X = B - ˙ C
14 hlcgreq.6 ⊢ φ → A - ˙ Y = B - ˙ C
15 eqid ⊢ Itv ⁡ G = Itv ⁡ G
16 1 15 3 7 4 11 hlgrcl1 ⊢ φ → X ∈ P
17 1 15 3 7 4 12 hlgrcl1 ⊢ φ → Y ∈ P
18 1 15 3 4 5 6 7 8 2 9 10 16 17 11 12 13 14 hlcgreulem ⊢ φ → X = Y