Metamath Proof Explorer


Theorem hlhgt4

Description: A Hilbert lattice has a height of at least 4. (Contributed by NM, 4-Dec-2011)

Ref Expression
Hypotheses hlhgt4.b ⊢ B = Base K
hlhgt4.s ⊢ < ˙ = < K
hlhgt4.z ⊢ 0 ˙ = 0. ⁡ K
hlhgt4.u ⊢ 1 ˙ = 1. ⁡ K
Assertion hlhgt4 ⊢ K ∈ HL → ∃ x ∈ B ∃ y ∈ B ∃ z ∈ B 0 ˙ < ˙ x ∧ x < ˙ y ∧ y < ˙ z ∧ z < ˙ 1 ˙

Proof

Step Hyp Ref Expression
1 hlhgt4.b ⊢ B = Base K
2 hlhgt4.s ⊢ < ˙ = < K
3 hlhgt4.z ⊢ 0 ˙ = 0. ⁡ K
4 hlhgt4.u ⊢ 1 ˙ = 1. ⁡ K
5 eqid ⊢ ≤ K = ≤ K
6 eqid ⊢ join ⁡ K = join ⁡ K
7 eqid ⊢ Atoms ⁡ K = Atoms ⁡ K
8 1 5 2 6 3 4 7 ishlat2 ⊢ K ∈ HL ↔ K ∈ OML ∧ K ∈ CLat ∧ K ∈ AtLat ∧ ∀ x ∈ Atoms ⁡ K ∀ y ∈ Atoms ⁡ K x ≠ y → ∃ z ∈ Atoms ⁡ K z ≠ x ∧ z ≠ y ∧ z ≤ K x join ⁡ K y ∧ ∀ z ∈ B ¬ x ≤ K z ∧ x ≤ K z join ⁡ K y → y ≤ K z join ⁡ K x ∧ ∃ x ∈ B ∃ y ∈ B ∃ z ∈ B 0 ˙ < ˙ x ∧ x < ˙ y ∧ y < ˙ z ∧ z < ˙ 1 ˙
9 simprr ⊢ K ∈ OML ∧ K ∈ CLat ∧ K ∈ AtLat ∧ ∀ x ∈ Atoms ⁡ K ∀ y ∈ Atoms ⁡ K x ≠ y → ∃ z ∈ Atoms ⁡ K z ≠ x ∧ z ≠ y ∧ z ≤ K x join ⁡ K y ∧ ∀ z ∈ B ¬ x ≤ K z ∧ x ≤ K z join ⁡ K y → y ≤ K z join ⁡ K x ∧ ∃ x ∈ B ∃ y ∈ B ∃ z ∈ B 0 ˙ < ˙ x ∧ x < ˙ y ∧ y < ˙ z ∧ z < ˙ 1 ˙ → ∃ x ∈ B ∃ y ∈ B ∃ z ∈ B 0 ˙ < ˙ x ∧ x < ˙ y ∧ y < ˙ z ∧ z < ˙ 1 ˙
10 8 9 sylbi ⊢ K ∈ HL → ∃ x ∈ B ∃ y ∈ B ∃ z ∈ B 0 ˙ < ˙ x ∧ x < ˙ y ∧ y < ˙ z ∧ z < ˙ 1 ˙