Metamath Proof Explorer


Theorem hmphtr

Description: "Is homeomorphic to" is transitive. (Contributed by FL, 9-Mar-2007) (Revised by Mario Carneiro, 23-Aug-2015)

Ref Expression
Assertion hmphtr ⊢ J ≃ K ∧ K ≃ L → J ≃ L

Proof

Step Hyp Ref Expression
1 hmph ⊢ J ≃ K ↔ J Homeo K ≠ ∅
2 hmph ⊢ K ≃ L ↔ K Homeo L ≠ ∅
3 n0 ⊢ J Homeo K ≠ ∅ ↔ ∃ f f ∈ J Homeo K
4 n0 ⊢ K Homeo L ≠ ∅ ↔ ∃ g g ∈ K Homeo L
5 exdistrv ⊢ ∃ f ∃ g f ∈ J Homeo K ∧ g ∈ K Homeo L ↔ ∃ f f ∈ J Homeo K ∧ ∃ g g ∈ K Homeo L
6 hmeoco ⊢ f ∈ J Homeo K ∧ g ∈ K Homeo L → g ∘ f ∈ J Homeo L
7 hmphi ⊢ g ∘ f ∈ J Homeo L → J ≃ L
8 6 7 syl ⊢ f ∈ J Homeo K ∧ g ∈ K Homeo L → J ≃ L
9 8 exlimivv ⊢ ∃ f ∃ g f ∈ J Homeo K ∧ g ∈ K Homeo L → J ≃ L
10 5 9 sylbir ⊢ ∃ f f ∈ J Homeo K ∧ ∃ g g ∈ K Homeo L → J ≃ L
11 3 4 10 syl2anb ⊢ J Homeo K ≠ ∅ ∧ K Homeo L ≠ ∅ → J ≃ L
12 1 2 11 syl2anb ⊢ J ≃ K ∧ K ≃ L → J ≃ L