Metamath Proof Explorer


Theorem idinxpssinxp4

Description: Identity intersection with a square Cartesian product in subclass relation with an intersection with the same Cartesian product (see also idinxpssinxp2 ). (Contributed by Peter Mazsa, 8-Mar-2019)

Ref Expression
Assertion idinxpssinxp4 ⊢ ∀ x ∈ A ∀ y ∈ A x = y → x R y ↔ ∀ x ∈ A x R x

Proof

Step Hyp Ref Expression
1 idinxpssinxp ⊢ I ∩ A × A ⊆ R ∩ A × A ↔ ∀ x ∈ A ∀ y ∈ A x = y → x R y
2 idinxpssinxp2 ⊢ I ∩ A × A ⊆ R ∩ A × A ↔ ∀ x ∈ A x R x
3 1 2 bitr3i ⊢ ∀ x ∈ A ∀ y ∈ A x = y → x R y ↔ ∀ x ∈ A x R x