Metamath Proof Explorer


Theorem idnmhm

Description: The identity operator is a bounded linear operator. (Contributed by Mario Carneiro, 20-Oct-2015)

Ref Expression
Hypothesis 0nmhm.1 ⊢ V = Base S
Assertion idnmhm ⊢ S ∈ NrmMod → I ↾ V ∈ S NMHom S

Proof

Step Hyp Ref Expression
1 0nmhm.1 ⊢ V = Base S
2 id ⊢ S ∈ NrmMod → S ∈ NrmMod
3 nlmlmod ⊢ S ∈ NrmMod → S ∈ LMod
4 1 idlmhm ⊢ S ∈ LMod → I ↾ V ∈ S LMHom S
5 3 4 syl ⊢ S ∈ NrmMod → I ↾ V ∈ S LMHom S
6 nlmngp ⊢ S ∈ NrmMod → S ∈ NrmGrp
7 1 idnghm ⊢ S ∈ NrmGrp → I ↾ V ∈ S NGHom S
8 6 7 syl ⊢ S ∈ NrmMod → I ↾ V ∈ S NGHom S
9 5 8 jca ⊢ S ∈ NrmMod → I ↾ V ∈ S LMHom S ∧ I ↾ V ∈ S NGHom S
10 isnmhm ⊢ I ↾ V ∈ S NMHom S ↔ S ∈ NrmMod ∧ S ∈ NrmMod ∧ I ↾ V ∈ S LMHom S ∧ I ↾ V ∈ S NGHom S
11 2 2 9 10 syl21anbrc ⊢ S ∈ NrmMod → I ↾ V ∈ S NMHom S