Metamath Proof Explorer


Theorem idomdomd

Description: An integral domain is a domain. (Contributed by Thierry Arnoux, 22-Mar-2025)

Ref Expression
Hypothesis idomringd.1 ⊢ φ → R ∈ IDomn
Assertion idomdomd ⊢ φ → R ∈ Domn

Proof

Step Hyp Ref Expression
1 idomringd.1 ⊢ φ → R ∈ IDomn
2 df-idom ⊢ IDomn = CRing ∩ Domn
3 1 2 eleqtrdi ⊢ φ → R ∈ CRing ∩ Domn
4 3 elin2d ⊢ φ → R ∈ Domn