Metamath Proof Explorer


Theorem ifeq2d

Description: Equality deduction for conditional operator. (Contributed by NM, 16-Feb-2005)

Ref Expression
Hypothesis ifeq1d.1 φ A = B
Assertion ifeq2d φ if ψ C A = if ψ C B

Proof

Step Hyp Ref Expression
1 ifeq1d.1 φ A = B
2 ifeq2 A = B if ψ C A = if ψ C B
3 1 2 syl φ if ψ C A = if ψ C B