Metamath Proof Explorer


Theorem iineq12dv

Description: Equality deduction for indexed intersection. (Contributed by Glauco Siliprandi, 26-Jun-2021) Remove DV conditions. (Revised by GG, 1-Sep-2025)

Ref Expression
Hypotheses iineq12dv.1 ⊢ φ → A = B
iineq12dv.2 ⊢ φ ∧ x ∈ B → C = D
Assertion iineq12dv ⊢ φ → ⋂ x ∈ A C = ⋂ x ∈ B D

Proof

Step Hyp Ref Expression
1 iineq12dv.1 ⊢ φ → A = B
2 iineq12dv.2 ⊢ φ ∧ x ∈ B → C = D
3 1 eleq2d ⊢ φ → x ∈ A ↔ x ∈ B
4 3 imbi1d ⊢ φ → x ∈ A → t ∈ C ↔ x ∈ B → t ∈ C
5 4 ralbidv2 ⊢ φ → ∀ x ∈ A t ∈ C ↔ ∀ x ∈ B t ∈ C
6 5 abbidv ⊢ φ → t | ∀ x ∈ A t ∈ C = t | ∀ x ∈ B t ∈ C
7 df-iin ⊢ ⋂ x ∈ A C = t | ∀ x ∈ A t ∈ C
8 df-iin ⊢ ⋂ x ∈ B C = t | ∀ x ∈ B t ∈ C
9 6 7 8 3eqtr4g ⊢ φ → ⋂ x ∈ A C = ⋂ x ∈ B C
10 2 iineq2dv ⊢ φ → ⋂ x ∈ B C = ⋂ x ∈ B D
11 9 10 eqtrd ⊢ φ → ⋂ x ∈ A C = ⋂ x ∈ B D