Metamath Proof Explorer


Theorem imsubd

Description: Imaginary part distributes over subtraction. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypotheses recld.1 ⊢ φ → A ∈ ℂ
readdd.2 ⊢ φ → B ∈ ℂ
Assertion imsubd ⊢ φ → ℑ ⁡ A − B = ℑ ⁡ A − ℑ ⁡ B

Proof

Step Hyp Ref Expression
1 recld.1 ⊢ φ → A ∈ ℂ
2 readdd.2 ⊢ φ → B ∈ ℂ
3 imsub ⊢ A ∈ ℂ ∧ B ∈ ℂ → ℑ ⁡ A − B = ℑ ⁡ A − ℑ ⁡ B
4 1 2 3 syl2anc ⊢ φ → ℑ ⁡ A − B = ℑ ⁡ A − ℑ ⁡ B