Metamath Proof Explorer


Theorem in13

Description: A rearrangement of intersection. (Contributed by NM, 27-Aug-2012)

Ref Expression
Assertion in13 A B C = C B A

Proof

Step Hyp Ref Expression
1 in32 B C A = B A C
2 incom A B C = B C A
3 incom C B A = B A C
4 1 2 3 3eqtr4i A B C = C B A