Metamath Proof Explorer


Theorem indconst1

Description: Indicator of the whole set. (Contributed by Thierry Arnoux, 25-Jan-2026)

Ref Expression
Assertion indconst1 ⊢ O ∈ V → 𝟙 O ⁡ O = O × 1

Proof

Step Hyp Ref Expression
1 ssid ⊢ O ⊆ O
2 indval2 ⊢ O ∈ V ∧ O ⊆ O → 𝟙 O ⁡ O = O × 1 ∪ O ∖ O × 0
3 1 2 mpan2 ⊢ O ∈ V → 𝟙 O ⁡ O = O × 1 ∪ O ∖ O × 0
4 difid ⊢ O ∖ O = ∅
5 4 xpeq1i ⊢ O ∖ O × 0 = ∅ × 0
6 0xp ⊢ ∅ × 0 = ∅
7 5 6 eqtri ⊢ O ∖ O × 0 = ∅
8 7 a1i ⊢ O ∈ V → O ∖ O × 0 = ∅
9 8 uneq2d ⊢ O ∈ V → O × 1 ∪ O ∖ O × 0 = O × 1 ∪ ∅
10 un0 ⊢ O × 1 ∪ ∅ = O × 1
11 10 a1i ⊢ O ∈ V → O × 1 ∪ ∅ = O × 1
12 3 9 11 3eqtrd ⊢ O ∈ V → 𝟙 O ⁡ O = O × 1