Metamath Proof Explorer


Theorem indif1

Description: Bring an intersection in and out of a class difference. (Contributed by Mario Carneiro, 15-May-2015)

Ref Expression
Assertion indif1 A C B = A B C

Proof

Step Hyp Ref Expression
1 indif2 B A C = B A C
2 incom B A C = A C B
3 incom B A = A B
4 3 difeq1i B A C = A B C
5 1 2 4 3eqtr3i A C B = A B C