Metamath Proof Explorer


Theorem indifcom

Description: Commutation law for intersection and difference. (Contributed by Scott Fenton, 18-Feb-2013)

Ref Expression
Assertion indifcom A B C = B A C

Proof

Step Hyp Ref Expression
1 incom A B = B A
2 1 difeq1i A B C = B A C
3 indif2 A B C = A B C
4 indif2 B A C = B A C
5 2 3 4 3eqtr4i A B C = B A C