Metamath Proof Explorer


Theorem indistps2ALT

Description: The indiscrete topology on a set A expressed as a topological space, using direct component assignments. Here we show how to derive the direct component assignment version indistps2 from the structural version indistps . (Contributed by NM, 24-Oct-2012) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Hypotheses indistps2ALT.a Base K = A
indistps2ALT.j TopOpen K = A
Assertion indistps2ALT K TopSp

Proof

Step Hyp Ref Expression
1 indistps2ALT.a Base K = A
2 indistps2ALT.j TopOpen K = A
3 fvex Base K V
4 1 3 eqeltrri A V
5 indistopon A V A TopOn A
6 4 5 ax-mp A TopOn A
7 1 eqcomi A = Base K
8 2 eqcomi A = TopOpen K
9 7 8 istps K TopSp A TopOn A
10 6 9 mpbir K TopSp