Metamath Proof Explorer


Theorem indistpsALTOLD

Description: Obsolete proof of indistpsALT as of 31-Oct-2024. The indiscrete topology on a set A expressed as a topological space. Here we show how to derive the structural version indistps from the direct component assignment version indistps2 . (Contributed by NM, 24-Oct-2012) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Hypotheses indistpsALT.a A V
indistpsALT.k K = Base ndx A TopSet ndx A
Assertion indistpsALTOLD K TopSp

Proof

Step Hyp Ref Expression
1 indistpsALT.a A V
2 indistpsALT.k K = Base ndx A TopSet ndx A
3 indistopon A V A TopOn A
4 df-tset TopSet = Slot 9
5 1lt9 1 < 9
6 9nn 9
7 2 4 5 6 2strbas A V A = Base K
8 1 7 ax-mp A = Base K
9 prex A V
10 2 4 5 6 2strop A V A = TopSet K
11 9 10 ax-mp A = TopSet K
12 8 11 tsettps A TopOn A K TopSp
13 1 3 12 mp2b K TopSp