Metamath Proof Explorer


Theorem indistpsx

Description: The indiscrete topology on a set A expressed as a topological space, using explicit structure component references. Compare with indistps and indistps2 . The advantage of this version is that the actual function for the structure is evident, and df-ndx is not needed, nor any other special definition outside of basic set theory. The disadvantage is that if the indices of the component definitions df-base and df-tset are changed in the future, this theorem will also have to be changed. Note: This theorem has hard-coded structure indices for demonstration purposes. It is not intended for general use; use indistps instead. (New usage is discouraged.) (Contributed by FL, 19-Jul-2006)

Ref Expression
Hypotheses indistpsx.a A V
indistpsx.k K = 1 A 9 A
Assertion indistpsx K TopSp

Proof

Step Hyp Ref Expression
1 indistpsx.a A V
2 indistpsx.k K = 1 A 9 A
3 basendx Base ndx = 1
4 3 opeq1i Base ndx A = 1 A
5 tsetndx TopSet ndx = 9
6 5 opeq1i TopSet ndx A = 9 A
7 4 6 preq12i Base ndx A TopSet ndx A = 1 A 9 A
8 2 7 eqtr4i K = Base ndx A TopSet ndx A
9 indistopon A V A TopOn A
10 1 9 ax-mp A TopOn A
11 10 toponunii A = A
12 indistop A Top
13 8 11 12 eltpsi K TopSp