Metamath Proof Explorer


Theorem ineqcomi

Description: Two ways of expressing that two classes have a given intersection. Inference form of ineqcom . Disjointness inference when C = (/) . (Contributed by Peter Mazsa, 26-Mar-2017) (Proof shortened by SN, 20-Sep-2024)

Ref Expression
Hypothesis ineqcomi.1 A B = C
Assertion ineqcomi B A = C

Proof

Step Hyp Ref Expression
1 ineqcomi.1 A B = C
2 incom B A = A B
3 2 1 eqtri B A = C