Metamath Proof Explorer


Theorem inf3lem1

Description: Lemma for our Axiom of Infinity => standard Axiom of Infinity. See inf3 for detailed description. (Contributed by NM, 28-Oct-1996)

Ref Expression
Hypotheses inf3lem.1 ⊢ G = y ∈ V ⟼ w ∈ x | w ∩ x ⊆ y
inf3lem.2 ⊢ F = rec ⁡ G ∅ ↾ ω
inf3lem.3 ⊢ A ∈ V
inf3lem.4 ⊢ B ∈ V
Assertion inf3lem1 ⊢ A ∈ ω → F ⁡ A ⊆ F ⁡ suc ⁡ A

Proof

Step Hyp Ref Expression
1 inf3lem.1 ⊢ G = y ∈ V ⟼ w ∈ x | w ∩ x ⊆ y
2 inf3lem.2 ⊢ F = rec ⁡ G ∅ ↾ ω
3 inf3lem.3 ⊢ A ∈ V
4 inf3lem.4 ⊢ B ∈ V
5 fveq2 ⊢ v = ∅ → F ⁡ v = F ⁡ ∅
6 suceq ⊢ v = ∅ → suc ⁡ v = suc ⁡ ∅
7 6 fveq2d ⊢ v = ∅ → F ⁡ suc ⁡ v = F ⁡ suc ⁡ ∅
8 5 7 sseq12d ⊢ v = ∅ → F ⁡ v ⊆ F ⁡ suc ⁡ v ↔ F ⁡ ∅ ⊆ F ⁡ suc ⁡ ∅
9 fveq2 ⊢ v = u → F ⁡ v = F ⁡ u
10 suceq ⊢ v = u → suc ⁡ v = suc ⁡ u
11 10 fveq2d ⊢ v = u → F ⁡ suc ⁡ v = F ⁡ suc ⁡ u
12 9 11 sseq12d ⊢ v = u → F ⁡ v ⊆ F ⁡ suc ⁡ v ↔ F ⁡ u ⊆ F ⁡ suc ⁡ u
13 fveq2 ⊢ v = suc ⁡ u → F ⁡ v = F ⁡ suc ⁡ u
14 suceq ⊢ v = suc ⁡ u → suc ⁡ v = suc ⁡ suc ⁡ u
15 14 fveq2d ⊢ v = suc ⁡ u → F ⁡ suc ⁡ v = F ⁡ suc ⁡ suc ⁡ u
16 13 15 sseq12d ⊢ v = suc ⁡ u → F ⁡ v ⊆ F ⁡ suc ⁡ v ↔ F ⁡ suc ⁡ u ⊆ F ⁡ suc ⁡ suc ⁡ u
17 fveq2 ⊢ v = A → F ⁡ v = F ⁡ A
18 suceq ⊢ v = A → suc ⁡ v = suc ⁡ A
19 18 fveq2d ⊢ v = A → F ⁡ suc ⁡ v = F ⁡ suc ⁡ A
20 17 19 sseq12d ⊢ v = A → F ⁡ v ⊆ F ⁡ suc ⁡ v ↔ F ⁡ A ⊆ F ⁡ suc ⁡ A
21 1 2 3 3 inf3lemb ⊢ F ⁡ ∅ = ∅
22 0ss ⊢ ∅ ⊆ F ⁡ suc ⁡ ∅
23 21 22 eqsstri ⊢ F ⁡ ∅ ⊆ F ⁡ suc ⁡ ∅
24 sstr2 ⊢ v ∩ x ⊆ F ⁡ u → F ⁡ u ⊆ F ⁡ suc ⁡ u → v ∩ x ⊆ F ⁡ suc ⁡ u
25 24 com12 ⊢ F ⁡ u ⊆ F ⁡ suc ⁡ u → v ∩ x ⊆ F ⁡ u → v ∩ x ⊆ F ⁡ suc ⁡ u
26 25 anim2d ⊢ F ⁡ u ⊆ F ⁡ suc ⁡ u → v ∈ x ∧ v ∩ x ⊆ F ⁡ u → v ∈ x ∧ v ∩ x ⊆ F ⁡ suc ⁡ u
27 vex ⊢ u ∈ V
28 1 2 27 3 inf3lemc ⊢ u ∈ ω → F ⁡ suc ⁡ u = G ⁡ F ⁡ u
29 28 eleq2d ⊢ u ∈ ω → v ∈ F ⁡ suc ⁡ u ↔ v ∈ G ⁡ F ⁡ u
30 vex ⊢ v ∈ V
31 fvex ⊢ F ⁡ u ∈ V
32 1 2 30 31 inf3lema ⊢ v ∈ G ⁡ F ⁡ u ↔ v ∈ x ∧ v ∩ x ⊆ F ⁡ u
33 29 32 bitrdi ⊢ u ∈ ω → v ∈ F ⁡ suc ⁡ u ↔ v ∈ x ∧ v ∩ x ⊆ F ⁡ u
34 peano2b ⊢ u ∈ ω ↔ suc ⁡ u ∈ ω
35 27 sucex ⊢ suc ⁡ u ∈ V
36 1 2 35 3 inf3lemc ⊢ suc ⁡ u ∈ ω → F ⁡ suc ⁡ suc ⁡ u = G ⁡ F ⁡ suc ⁡ u
37 34 36 sylbi ⊢ u ∈ ω → F ⁡ suc ⁡ suc ⁡ u = G ⁡ F ⁡ suc ⁡ u
38 37 eleq2d ⊢ u ∈ ω → v ∈ F ⁡ suc ⁡ suc ⁡ u ↔ v ∈ G ⁡ F ⁡ suc ⁡ u
39 fvex ⊢ F ⁡ suc ⁡ u ∈ V
40 1 2 30 39 inf3lema ⊢ v ∈ G ⁡ F ⁡ suc ⁡ u ↔ v ∈ x ∧ v ∩ x ⊆ F ⁡ suc ⁡ u
41 38 40 bitrdi ⊢ u ∈ ω → v ∈ F ⁡ suc ⁡ suc ⁡ u ↔ v ∈ x ∧ v ∩ x ⊆ F ⁡ suc ⁡ u
42 33 41 imbi12d ⊢ u ∈ ω → v ∈ F ⁡ suc ⁡ u → v ∈ F ⁡ suc ⁡ suc ⁡ u ↔ v ∈ x ∧ v ∩ x ⊆ F ⁡ u → v ∈ x ∧ v ∩ x ⊆ F ⁡ suc ⁡ u
43 26 42 imbitrrid ⊢ u ∈ ω → F ⁡ u ⊆ F ⁡ suc ⁡ u → v ∈ F ⁡ suc ⁡ u → v ∈ F ⁡ suc ⁡ suc ⁡ u
44 43 imp ⊢ u ∈ ω ∧ F ⁡ u ⊆ F ⁡ suc ⁡ u → v ∈ F ⁡ suc ⁡ u → v ∈ F ⁡ suc ⁡ suc ⁡ u
45 44 ssrdv ⊢ u ∈ ω ∧ F ⁡ u ⊆ F ⁡ suc ⁡ u → F ⁡ suc ⁡ u ⊆ F ⁡ suc ⁡ suc ⁡ u
46 45 ex ⊢ u ∈ ω → F ⁡ u ⊆ F ⁡ suc ⁡ u → F ⁡ suc ⁡ u ⊆ F ⁡ suc ⁡ suc ⁡ u
47 8 12 16 20 23 46 finds ⊢ A ∈ ω → F ⁡ A ⊆ F ⁡ suc ⁡ A