Metamath Proof Explorer


Theorem infeq5

Description: The statement "there exists a set that is a proper subset of its union" is equivalent to the Axiom of Infinity (shown on the right-hand side in the form of omex .) The left-hand side provides us with a very short way to express the Axiom of Infinity using only elementary symbols. This proof of equivalence does not depend on the Axiom of Infinity. (Contributed by NM, 23-Mar-2004) (Revised by Mario Carneiro, 16-Nov-2014)

Ref Expression
Assertion infeq5 ⊢ ∃ x x ⊂ ⋃ x ↔ ω ∈ V

Proof

Step Hyp Ref Expression
1 df-pss ⊢ x ⊂ ⋃ x ↔ x ⊆ ⋃ x ∧ x ≠ ⋃ x
2 unieq ⊢ x = ∅ → ⋃ x = ⋃ ∅
3 uni0 ⊢ ⋃ ∅ = ∅
4 2 3 eqtr2di ⊢ x = ∅ → ∅ = ⋃ x
5 eqtr ⊢ x = ∅ ∧ ∅ = ⋃ x → x = ⋃ x
6 4 5 mpdan ⊢ x = ∅ → x = ⋃ x
7 6 necon3i ⊢ x ≠ ⋃ x → x ≠ ∅
8 7 anim1i ⊢ x ≠ ⋃ x ∧ x ⊆ ⋃ x → x ≠ ∅ ∧ x ⊆ ⋃ x
9 8 ancoms ⊢ x ⊆ ⋃ x ∧ x ≠ ⋃ x → x ≠ ∅ ∧ x ⊆ ⋃ x
10 1 9 sylbi ⊢ x ⊂ ⋃ x → x ≠ ∅ ∧ x ⊆ ⋃ x
11 10 eximi ⊢ ∃ x x ⊂ ⋃ x → ∃ x x ≠ ∅ ∧ x ⊆ ⋃ x
12 eqid ⊢ y ∈ V ⟼ w ∈ x | w ∩ x ⊆ y = y ∈ V ⟼ w ∈ x | w ∩ x ⊆ y
13 eqid ⊢ rec ⁡ y ∈ V ⟼ w ∈ x | w ∩ x ⊆ y ∅ ↾ ω = rec ⁡ y ∈ V ⟼ w ∈ x | w ∩ x ⊆ y ∅ ↾ ω
14 vex ⊢ x ∈ V
15 12 13 14 14 inf3lem7 ⊢ x ≠ ∅ ∧ x ⊆ ⋃ x → ω ∈ V
16 15 exlimiv ⊢ ∃ x x ≠ ∅ ∧ x ⊆ ⋃ x → ω ∈ V
17 11 16 syl ⊢ ∃ x x ⊂ ⋃ x → ω ∈ V
18 infeq5i ⊢ ω ∈ V → ∃ x x ⊂ ⋃ x
19 17 18 impbii ⊢ ∃ x x ⊂ ⋃ x ↔ ω ∈ V