Metamath Proof Explorer


Theorem inin

Description: Intersection with an intersection. (Contributed by Thierry Arnoux, 27-Dec-2016)

Ref Expression
Assertion inin A A B = A B

Proof

Step Hyp Ref Expression
1 in13 A A B = B A A
2 inidm A A = A
3 2 ineq2i B A A = B A
4 incom B A = A B
5 1 3 4 3eqtri A A B = A B