Metamath Proof Explorer


Theorem inin

Description: Intersection with an intersection. (Contributed by Thierry Arnoux, 27-Dec-2016)

Ref Expression
Assertion inin ⊢ A ∩ A ∩ B = A ∩ B

Proof

Step Hyp Ref Expression
1 in13 ⊢ A ∩ A ∩ B = B ∩ A ∩ A
2 inidm ⊢ A ∩ A = A
3 2 ineq2i ⊢ B ∩ A ∩ A = B ∩ A
4 incom ⊢ B ∩ A = A ∩ B
5 1 3 4 3eqtri ⊢ A ∩ A ∩ B = A ∩ B