Metamath Proof Explorer


Theorem inlidl

Description: The intersection of two ideals is an ideal. (Contributed by Jeff Madsen, 16-Jun-2011) (Revised by AV, 28-Jun-2026)

Ref Expression
Assertion inlidl ⊢ R ∈ Ring ∧ I ∈ LIdeal ⁡ R ∧ J ∈ LIdeal ⁡ R → I ∩ J ∈ LIdeal ⁡ R

Proof

Step Hyp Ref Expression
1 intprg ⊢ I ∈ LIdeal ⁡ R ∧ J ∈ LIdeal ⁡ R → ⋂ I J = I ∩ J
2 1 3adant1 ⊢ R ∈ Ring ∧ I ∈ LIdeal ⁡ R ∧ J ∈ LIdeal ⁡ R → ⋂ I J = I ∩ J
3 simp1 ⊢ R ∈ Ring ∧ I ∈ LIdeal ⁡ R ∧ J ∈ LIdeal ⁡ R → R ∈ Ring
4 prnzg ⊢ I ∈ LIdeal ⁡ R → I J ≠ ∅
5 4 3ad2ant2 ⊢ R ∈ Ring ∧ I ∈ LIdeal ⁡ R ∧ J ∈ LIdeal ⁡ R → I J ≠ ∅
6 prssi ⊢ I ∈ LIdeal ⁡ R ∧ J ∈ LIdeal ⁡ R → I J ⊆ LIdeal ⁡ R
7 6 3adant1 ⊢ R ∈ Ring ∧ I ∈ LIdeal ⁡ R ∧ J ∈ LIdeal ⁡ R → I J ⊆ LIdeal ⁡ R
8 intlidl ⊢ R ∈ Ring ∧ I J ≠ ∅ ∧ I J ⊆ LIdeal ⁡ R → ⋂ I J ∈ LIdeal ⁡ R
9 3 5 7 8 syl3anc ⊢ R ∈ Ring ∧ I ∈ LIdeal ⁡ R ∧ J ∈ LIdeal ⁡ R → ⋂ I J ∈ LIdeal ⁡ R
10 2 9 eqeltrrd ⊢ R ∈ Ring ∧ I ∈ LIdeal ⁡ R ∧ J ∈ LIdeal ⁡ R → I ∩ J ∈ LIdeal ⁡ R