Metamath Proof Explorer


Theorem invpropd

Description: Two structures with the same base, hom-sets and composition operation have the same inverses. (Contributed by Zhi Wang, 27-Oct-2025)

Ref Expression
Hypotheses sectpropd.1 ⊢ φ → Hom 𝑓 ⁡ C = Hom 𝑓 ⁡ D
sectpropd.2 ⊢ φ → comp 𝑓 ⁡ C = comp 𝑓 ⁡ D
Assertion invpropd ⊢ φ → Inv ⁡ C = Inv ⁡ D

Proof

Step Hyp Ref Expression
1 sectpropd.1 ⊢ φ → Hom 𝑓 ⁡ C = Hom 𝑓 ⁡ D
2 sectpropd.2 ⊢ φ → comp 𝑓 ⁡ C = comp 𝑓 ⁡ D
3 1 2 invpropdlem ⊢ φ ∧ f ∈ Inv ⁡ C → f ∈ Inv ⁡ D
4 1 eqcomd ⊢ φ → Hom 𝑓 ⁡ D = Hom 𝑓 ⁡ C
5 2 eqcomd ⊢ φ → comp 𝑓 ⁡ D = comp 𝑓 ⁡ C
6 4 5 invpropdlem ⊢ φ ∧ f ∈ Inv ⁡ D → f ∈ Inv ⁡ C
7 3 6 impbida ⊢ φ → f ∈ Inv ⁡ C ↔ f ∈ Inv ⁡ D
8 7 eqrdv ⊢ φ → Inv ⁡ C = Inv ⁡ D