Metamath Proof Explorer


Theorem isgrpd2e

Description: Deduce a group from its properties. In this version of isgrpd2 , we don't assume there is an expression for the inverse of x . (Contributed by NM, 10-Aug-2013)

Ref Expression
Hypotheses isgrpd2.b ⊢ φ → B = Base G
isgrpd2.p ⊢ φ → + ˙ = + G
isgrpd2.z ⊢ φ → 0 ˙ = 0 G
isgrpd2.g ⊢ φ → G ∈ Mnd
isgrpd2e.n ⊢ φ ∧ x ∈ B → ∃ y ∈ B y + ˙ x = 0 ˙
Assertion isgrpd2e ⊢ φ → G ∈ Grp

Proof

Step Hyp Ref Expression
1 isgrpd2.b ⊢ φ → B = Base G
2 isgrpd2.p ⊢ φ → + ˙ = + G
3 isgrpd2.z ⊢ φ → 0 ˙ = 0 G
4 isgrpd2.g ⊢ φ → G ∈ Mnd
5 isgrpd2e.n ⊢ φ ∧ x ∈ B → ∃ y ∈ B y + ˙ x = 0 ˙
6 5 ralrimiva ⊢ φ → ∀ x ∈ B ∃ y ∈ B y + ˙ x = 0 ˙
7 2 oveqd ⊢ φ → y + ˙ x = y + G x
8 7 3 eqeq12d ⊢ φ → y + ˙ x = 0 ˙ ↔ y + G x = 0 G
9 1 8 rexeqbidv ⊢ φ → ∃ y ∈ B y + ˙ x = 0 ˙ ↔ ∃ y ∈ Base G y + G x = 0 G
10 1 9 raleqbidv ⊢ φ → ∀ x ∈ B ∃ y ∈ B y + ˙ x = 0 ˙ ↔ ∀ x ∈ Base G ∃ y ∈ Base G y + G x = 0 G
11 6 10 mpbid ⊢ φ → ∀ x ∈ Base G ∃ y ∈ Base G y + G x = 0 G
12 eqid ⊢ Base G = Base G
13 eqid ⊢ + G = + G
14 eqid ⊢ 0 G = 0 G
15 12 13 14 isgrp ⊢ G ∈ Grp ↔ G ∈ Mnd ∧ ∀ x ∈ Base G ∃ y ∈ Base G y + G x = 0 G
16 4 11 15 sylanbrc ⊢ φ → G ∈ Grp