Metamath Proof Explorer


Theorem islpln2a

Description: The predicate "is a lattice plane" for join of atoms. (Contributed by NM, 16-Jul-2012)

Ref Expression
Hypotheses islpln2a.l ⊢ ≤ ˙ = ≤ K
islpln2a.j ⊢ ∨ ˙ = join ⁡ K
islpln2a.a ⊢ A = Atoms ⁡ K
islpln2a.p ⊢ P = LPlanes ⁡ K
Assertion islpln2a ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → Q ∨ ˙ R ∨ ˙ S ∈ P ↔ Q ≠ R ∧ ¬ S ≤ ˙ Q ∨ ˙ R

Proof

Step Hyp Ref Expression
1 islpln2a.l ⊢ ≤ ˙ = ≤ K
2 islpln2a.j ⊢ ∨ ˙ = join ⁡ K
3 islpln2a.a ⊢ A = Atoms ⁡ K
4 islpln2a.p ⊢ P = LPlanes ⁡ K
5 oveq1 ⊢ Q = R → Q ∨ ˙ R = R ∨ ˙ R
6 2 3 hlatjidm ⊢ K ∈ HL ∧ R ∈ A → R ∨ ˙ R = R
7 6 3ad2antr2 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → R ∨ ˙ R = R
8 5 7 sylan9eqr ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Q = R → Q ∨ ˙ R = R
9 8 oveq1d ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Q = R → Q ∨ ˙ R ∨ ˙ S = R ∨ ˙ S
10 simpll ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Q = R → K ∈ HL
11 simplr2 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Q = R → R ∈ A
12 simplr3 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Q = R → S ∈ A
13 2 3 4 2atnelpln ⊢ K ∈ HL ∧ R ∈ A ∧ S ∈ A → ¬ R ∨ ˙ S ∈ P
14 10 11 12 13 syl3anc ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Q = R → ¬ R ∨ ˙ S ∈ P
15 9 14 eqneltrd ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Q = R → ¬ Q ∨ ˙ R ∨ ˙ S ∈ P
16 15 ex ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → Q = R → ¬ Q ∨ ˙ R ∨ ˙ S ∈ P
17 16 necon2ad ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → Q ∨ ˙ R ∨ ˙ S ∈ P → Q ≠ R
18 hllat ⊢ K ∈ HL → K ∈ Lat
19 18 adantr ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → K ∈ Lat
20 simpr3 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → S ∈ A
21 eqid ⊢ Base K = Base K
22 21 3 atbase ⊢ S ∈ A → S ∈ Base K
23 20 22 syl ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → S ∈ Base K
24 21 2 3 hlatjcl ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A → Q ∨ ˙ R ∈ Base K
25 24 3adant3r3 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → Q ∨ ˙ R ∈ Base K
26 21 1 2 latleeqj2 ⊢ K ∈ Lat ∧ S ∈ Base K ∧ Q ∨ ˙ R ∈ Base K → S ≤ ˙ Q ∨ ˙ R ↔ Q ∨ ˙ R ∨ ˙ S = Q ∨ ˙ R
27 19 23 25 26 syl3anc ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → S ≤ ˙ Q ∨ ˙ R ↔ Q ∨ ˙ R ∨ ˙ S = Q ∨ ˙ R
28 2 3 4 2atnelpln ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A → ¬ Q ∨ ˙ R ∈ P
29 28 3adant3r3 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → ¬ Q ∨ ˙ R ∈ P
30 eleq1 ⊢ Q ∨ ˙ R ∨ ˙ S = Q ∨ ˙ R → Q ∨ ˙ R ∨ ˙ S ∈ P ↔ Q ∨ ˙ R ∈ P
31 30 notbid ⊢ Q ∨ ˙ R ∨ ˙ S = Q ∨ ˙ R → ¬ Q ∨ ˙ R ∨ ˙ S ∈ P ↔ ¬ Q ∨ ˙ R ∈ P
32 29 31 syl5ibrcom ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → Q ∨ ˙ R ∨ ˙ S = Q ∨ ˙ R → ¬ Q ∨ ˙ R ∨ ˙ S ∈ P
33 27 32 sylbid ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → S ≤ ˙ Q ∨ ˙ R → ¬ Q ∨ ˙ R ∨ ˙ S ∈ P
34 33 con2d ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → Q ∨ ˙ R ∨ ˙ S ∈ P → ¬ S ≤ ˙ Q ∨ ˙ R
35 17 34 jcad ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → Q ∨ ˙ R ∨ ˙ S ∈ P → Q ≠ R ∧ ¬ S ≤ ˙ Q ∨ ˙ R
36 1 2 3 4 lplni2 ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A ∧ Q ≠ R ∧ ¬ S ≤ ˙ Q ∨ ˙ R → Q ∨ ˙ R ∨ ˙ S ∈ P
37 36 3expia ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → Q ≠ R ∧ ¬ S ≤ ˙ Q ∨ ˙ R → Q ∨ ˙ R ∨ ˙ S ∈ P
38 35 37 impbid ⊢ K ∈ HL ∧ Q ∈ A ∧ R ∈ A ∧ S ∈ A → Q ∨ ˙ R ∨ ˙ S ∈ P ↔ Q ≠ R ∧ ¬ S ≤ ˙ Q ∨ ˙ R