Metamath Proof Explorer


Theorem ismir

Description: Property of the image by the point inversion function. Definition 7.5 of Schwabhauser p. 49. (Contributed by Thierry Arnoux, 3-Jun-2019)

Ref Expression
Hypotheses mirval.p ⊢ P = Base G
mirval.d ⊢ - ˙ = dist ⁡ G
mirval.i ⊢ I = Itv ⁡ G
mirval.l ⊢ L = Line 𝒢 ⁡ G
mirval.s ⊢ S = pInv 𝒢 ⁡ G
mirval.g ⊢ φ → G ∈ 𝒢 Tarski
mirval.a ⊢ φ → A ∈ P
mirfv.m ⊢ M = S ⁡ A
mirfv.b ⊢ φ → B ∈ P
ismir.1 ⊢ φ → C ∈ P
ismir.2 ⊢ φ → A - ˙ C = A - ˙ B
ismir.3 ⊢ φ → A ∈ C I B
Assertion ismir ⊢ φ → C = M ⁡ B

Proof

Step Hyp Ref Expression
1 mirval.p ⊢ P = Base G
2 mirval.d ⊢ - ˙ = dist ⁡ G
3 mirval.i ⊢ I = Itv ⁡ G
4 mirval.l ⊢ L = Line 𝒢 ⁡ G
5 mirval.s ⊢ S = pInv 𝒢 ⁡ G
6 mirval.g ⊢ φ → G ∈ 𝒢 Tarski
7 mirval.a ⊢ φ → A ∈ P
8 mirfv.m ⊢ M = S ⁡ A
9 mirfv.b ⊢ φ → B ∈ P
10 ismir.1 ⊢ φ → C ∈ P
11 ismir.2 ⊢ φ → A - ˙ C = A - ˙ B
12 ismir.3 ⊢ φ → A ∈ C I B
13 1 2 3 4 5 6 7 8 9 mirfv ⊢ φ → M ⁡ B = ι z ∈ P | A - ˙ z = A - ˙ B ∧ A ∈ z I B
14 1 2 3 6 9 7 mirreu3 ⊢ φ → ∃! z ∈ P A - ˙ z = A - ˙ B ∧ A ∈ z I B
15 oveq2 ⊢ z = C → A - ˙ z = A - ˙ C
16 15 eqeq1d ⊢ z = C → A - ˙ z = A - ˙ B ↔ A - ˙ C = A - ˙ B
17 oveq1 ⊢ z = C → z I B = C I B
18 17 eleq2d ⊢ z = C → A ∈ z I B ↔ A ∈ C I B
19 16 18 anbi12d ⊢ z = C → A - ˙ z = A - ˙ B ∧ A ∈ z I B ↔ A - ˙ C = A - ˙ B ∧ A ∈ C I B
20 19 riota2 ⊢ C ∈ P ∧ ∃! z ∈ P A - ˙ z = A - ˙ B ∧ A ∈ z I B → A - ˙ C = A - ˙ B ∧ A ∈ C I B ↔ ι z ∈ P | A - ˙ z = A - ˙ B ∧ A ∈ z I B = C
21 10 14 20 syl2anc ⊢ φ → A - ˙ C = A - ˙ B ∧ A ∈ C I B ↔ ι z ∈ P | A - ˙ z = A - ˙ B ∧ A ∈ z I B = C
22 11 12 21 mpbi2and ⊢ φ → ι z ∈ P | A - ˙ z = A - ˙ B ∧ A ∈ z I B = C
23 13 22 eqtr2d ⊢ φ → C = M ⁡ B