Metamath Proof Explorer


Theorem isopn2

Description: A subset of the underlying set of a topology is open iff its complement is closed. (Contributed by NM, 4-Oct-2006)

Ref Expression
Hypothesis iscld.1 ⊢ X = ⋃ J
Assertion isopn2 ⊢ J ∈ Top ∧ S ⊆ X → S ∈ J ↔ X ∖ S ∈ Clsd ⁡ J

Proof

Step Hyp Ref Expression
1 iscld.1 ⊢ X = ⋃ J
2 difss ⊢ X ∖ S ⊆ X
3 1 iscld2 ⊢ J ∈ Top ∧ X ∖ S ⊆ X → X ∖ S ∈ Clsd ⁡ J ↔ X ∖ X ∖ S ∈ J
4 2 3 mpan2 ⊢ J ∈ Top → X ∖ S ∈ Clsd ⁡ J ↔ X ∖ X ∖ S ∈ J
5 dfss4 ⊢ S ⊆ X ↔ X ∖ X ∖ S = S
6 5 biimpi ⊢ S ⊆ X → X ∖ X ∖ S = S
7 6 eleq1d ⊢ S ⊆ X → X ∖ X ∖ S ∈ J ↔ S ∈ J
8 4 7 sylan9bb ⊢ J ∈ Top ∧ S ⊆ X → X ∖ S ∈ Clsd ⁡ J ↔ S ∈ J
9 8 bicomd ⊢ J ∈ Top ∧ S ⊆ X → S ∈ J ↔ X ∖ S ∈ Clsd ⁡ J