Metamath Proof Explorer


Theorem isoselem

Description: Lemma for isose . (Contributed by Mario Carneiro, 23-Jun-2015)

Ref Expression
Hypotheses isofrlem.1 ⊢ φ → H Isom R , S A B
isofrlem.2 ⊢ φ → H x ∈ V
Assertion isoselem ⊢ φ → R Se A → S Se B

Proof

Step Hyp Ref Expression
1 isofrlem.1 ⊢ φ → H Isom R , S A B
2 isofrlem.2 ⊢ φ → H x ∈ V
3 dfse2 ⊢ R Se A ↔ ∀ z ∈ A A ∩ R -1 z ∈ V
4 3 biimpi ⊢ R Se A → ∀ z ∈ A A ∩ R -1 z ∈ V
5 4 r19.21bi ⊢ R Se A ∧ z ∈ A → A ∩ R -1 z ∈ V
6 5 expcom ⊢ z ∈ A → R Se A → A ∩ R -1 z ∈ V
7 6 adantl ⊢ φ ∧ z ∈ A → R Se A → A ∩ R -1 z ∈ V
8 imaeq2 ⊢ x = A ∩ R -1 z → H x = H A ∩ R -1 z
9 8 eleq1d ⊢ x = A ∩ R -1 z → H x ∈ V ↔ H A ∩ R -1 z ∈ V
10 9 imbi2d ⊢ x = A ∩ R -1 z → φ → H x ∈ V ↔ φ → H A ∩ R -1 z ∈ V
11 10 2 vtoclg ⊢ A ∩ R -1 z ∈ V → φ → H A ∩ R -1 z ∈ V
12 11 com12 ⊢ φ → A ∩ R -1 z ∈ V → H A ∩ R -1 z ∈ V
13 12 adantr ⊢ φ ∧ z ∈ A → A ∩ R -1 z ∈ V → H A ∩ R -1 z ∈ V
14 isoini ⊢ H Isom R , S A B ∧ z ∈ A → H A ∩ R -1 z = B ∩ S -1 H ⁡ z
15 1 14 sylan ⊢ φ ∧ z ∈ A → H A ∩ R -1 z = B ∩ S -1 H ⁡ z
16 15 eleq1d ⊢ φ ∧ z ∈ A → H A ∩ R -1 z ∈ V ↔ B ∩ S -1 H ⁡ z ∈ V
17 13 16 sylibd ⊢ φ ∧ z ∈ A → A ∩ R -1 z ∈ V → B ∩ S -1 H ⁡ z ∈ V
18 7 17 syld ⊢ φ ∧ z ∈ A → R Se A → B ∩ S -1 H ⁡ z ∈ V
19 18 ralrimdva ⊢ φ → R Se A → ∀ z ∈ A B ∩ S -1 H ⁡ z ∈ V
20 isof1o ⊢ H Isom R , S A B → H : A ⟶ 1-1 onto B
21 f1ofn ⊢ H : A ⟶ 1-1 onto B → H Fn A
22 sneq ⊢ y = H ⁡ z → y = H ⁡ z
23 22 imaeq2d ⊢ y = H ⁡ z → S -1 y = S -1 H ⁡ z
24 23 ineq2d ⊢ y = H ⁡ z → B ∩ S -1 y = B ∩ S -1 H ⁡ z
25 24 eleq1d ⊢ y = H ⁡ z → B ∩ S -1 y ∈ V ↔ B ∩ S -1 H ⁡ z ∈ V
26 25 ralrn ⊢ H Fn A → ∀ y ∈ ran ⁡ H B ∩ S -1 y ∈ V ↔ ∀ z ∈ A B ∩ S -1 H ⁡ z ∈ V
27 1 20 21 26 4syl ⊢ φ → ∀ y ∈ ran ⁡ H B ∩ S -1 y ∈ V ↔ ∀ z ∈ A B ∩ S -1 H ⁡ z ∈ V
28 f1ofo ⊢ H : A ⟶ 1-1 onto B → H : A ⟶ onto B
29 forn ⊢ H : A ⟶ onto B → ran ⁡ H = B
30 1 20 28 29 4syl ⊢ φ → ran ⁡ H = B
31 30 raleqdv ⊢ φ → ∀ y ∈ ran ⁡ H B ∩ S -1 y ∈ V ↔ ∀ y ∈ B B ∩ S -1 y ∈ V
32 27 31 bitr3d ⊢ φ → ∀ z ∈ A B ∩ S -1 H ⁡ z ∈ V ↔ ∀ y ∈ B B ∩ S -1 y ∈ V
33 19 32 sylibd ⊢ φ → R Se A → ∀ y ∈ B B ∩ S -1 y ∈ V
34 dfse2 ⊢ S Se B ↔ ∀ y ∈ B B ∩ S -1 y ∈ V
35 33 34 imbitrrdi ⊢ φ → R Se A → S Se B