Metamath Proof Explorer


Theorem ispsubsp2

Description: The predicate "is a projective subspace". (Contributed by NM, 13-Jan-2012)

Ref Expression
Hypotheses psubspset.l ⊢ ≤ ˙ = ≤ K
psubspset.j ⊢ ∨ ˙ = join ⁡ K
psubspset.a ⊢ A = Atoms ⁡ K
psubspset.s ⊢ S = PSubSp ⁡ K
Assertion ispsubsp2 ⊢ K ∈ D → X ∈ S ↔ X ⊆ A ∧ ∀ p ∈ A ∃ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X

Proof

Step Hyp Ref Expression
1 psubspset.l ⊢ ≤ ˙ = ≤ K
2 psubspset.j ⊢ ∨ ˙ = join ⁡ K
3 psubspset.a ⊢ A = Atoms ⁡ K
4 psubspset.s ⊢ S = PSubSp ⁡ K
5 1 2 3 4 ispsubsp ⊢ K ∈ D → X ∈ S ↔ X ⊆ A ∧ ∀ q ∈ X ∀ r ∈ X ∀ p ∈ A p ≤ ˙ q ∨ ˙ r → p ∈ X
6 ralcom ⊢ ∀ r ∈ X ∀ p ∈ A p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∀ p ∈ A ∀ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
7 r19.23v ⊢ ∀ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
8 7 ralbii ⊢ ∀ p ∈ A ∀ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∀ p ∈ A ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
9 6 8 bitri ⊢ ∀ r ∈ X ∀ p ∈ A p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∀ p ∈ A ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
10 9 ralbii ⊢ ∀ q ∈ X ∀ r ∈ X ∀ p ∈ A p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∀ q ∈ X ∀ p ∈ A ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
11 ralcom ⊢ ∀ q ∈ X ∀ p ∈ A ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∀ p ∈ A ∀ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
12 r19.23v ⊢ ∀ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∃ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
13 12 ralbii ⊢ ∀ p ∈ A ∀ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∀ p ∈ A ∃ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
14 11 13 bitri ⊢ ∀ q ∈ X ∀ p ∈ A ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∀ p ∈ A ∃ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
15 10 14 bitri ⊢ ∀ q ∈ X ∀ r ∈ X ∀ p ∈ A p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∀ p ∈ A ∃ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
16 15 a1i ⊢ K ∈ D → ∀ q ∈ X ∀ r ∈ X ∀ p ∈ A p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ ∀ p ∈ A ∃ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
17 16 anbi2d ⊢ K ∈ D → X ⊆ A ∧ ∀ q ∈ X ∀ r ∈ X ∀ p ∈ A p ≤ ˙ q ∨ ˙ r → p ∈ X ↔ X ⊆ A ∧ ∀ p ∈ A ∃ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X
18 5 17 bitrd ⊢ K ∈ D → X ∈ S ↔ X ⊆ A ∧ ∀ p ∈ A ∃ q ∈ X ∃ r ∈ X p ≤ ˙ q ∨ ˙ r → p ∈ X