Metamath Proof Explorer


Theorem istrnN

Description: The predicate "is a translation". (Contributed by NM, 4-Feb-2012) (New usage is discouraged.)

Ref Expression
Hypotheses trnset.a ⊢ A = Atoms ⁡ K
trnset.s ⊢ S = PSubSp ⁡ K
trnset.p ⊢ + ˙ = + 𝑃 ⁡ K
trnset.o ⊢ ⊥ ˙ = ⊥ 𝑃 ⁡ K
trnset.w ⊢ W = WAtoms ⁡ K
trnset.m ⊢ M = PAut ⁡ K
trnset.l ⊢ L = Dil ⁡ K
trnset.t ⊢ T = Trn ⁡ K
Assertion istrnN ⊢ K ∈ B ∧ D ∈ A → F ∈ T ⁡ D ↔ F ∈ L ⁡ D ∧ ∀ q ∈ W ⁡ D ∀ r ∈ W ⁡ D q + ˙ F ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ F ⁡ r ∩ ⊥ ˙ ⁡ D

Proof

Step Hyp Ref Expression
1 trnset.a ⊢ A = Atoms ⁡ K
2 trnset.s ⊢ S = PSubSp ⁡ K
3 trnset.p ⊢ + ˙ = + 𝑃 ⁡ K
4 trnset.o ⊢ ⊥ ˙ = ⊥ 𝑃 ⁡ K
5 trnset.w ⊢ W = WAtoms ⁡ K
6 trnset.m ⊢ M = PAut ⁡ K
7 trnset.l ⊢ L = Dil ⁡ K
8 trnset.t ⊢ T = Trn ⁡ K
9 1 2 3 4 5 6 7 8 trnsetN ⊢ K ∈ B ∧ D ∈ A → T ⁡ D = f ∈ L ⁡ D | ∀ q ∈ W ⁡ D ∀ r ∈ W ⁡ D q + ˙ f ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ f ⁡ r ∩ ⊥ ˙ ⁡ D
10 9 eleq2d ⊢ K ∈ B ∧ D ∈ A → F ∈ T ⁡ D ↔ F ∈ f ∈ L ⁡ D | ∀ q ∈ W ⁡ D ∀ r ∈ W ⁡ D q + ˙ f ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ f ⁡ r ∩ ⊥ ˙ ⁡ D
11 fveq1 ⊢ f = F → f ⁡ q = F ⁡ q
12 11 oveq2d ⊢ f = F → q + ˙ f ⁡ q = q + ˙ F ⁡ q
13 12 ineq1d ⊢ f = F → q + ˙ f ⁡ q ∩ ⊥ ˙ ⁡ D = q + ˙ F ⁡ q ∩ ⊥ ˙ ⁡ D
14 fveq1 ⊢ f = F → f ⁡ r = F ⁡ r
15 14 oveq2d ⊢ f = F → r + ˙ f ⁡ r = r + ˙ F ⁡ r
16 15 ineq1d ⊢ f = F → r + ˙ f ⁡ r ∩ ⊥ ˙ ⁡ D = r + ˙ F ⁡ r ∩ ⊥ ˙ ⁡ D
17 13 16 eqeq12d ⊢ f = F → q + ˙ f ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ f ⁡ r ∩ ⊥ ˙ ⁡ D ↔ q + ˙ F ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ F ⁡ r ∩ ⊥ ˙ ⁡ D
18 17 2ralbidv ⊢ f = F → ∀ q ∈ W ⁡ D ∀ r ∈ W ⁡ D q + ˙ f ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ f ⁡ r ∩ ⊥ ˙ ⁡ D ↔ ∀ q ∈ W ⁡ D ∀ r ∈ W ⁡ D q + ˙ F ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ F ⁡ r ∩ ⊥ ˙ ⁡ D
19 18 elrab ⊢ F ∈ f ∈ L ⁡ D | ∀ q ∈ W ⁡ D ∀ r ∈ W ⁡ D q + ˙ f ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ f ⁡ r ∩ ⊥ ˙ ⁡ D ↔ F ∈ L ⁡ D ∧ ∀ q ∈ W ⁡ D ∀ r ∈ W ⁡ D q + ˙ F ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ F ⁡ r ∩ ⊥ ˙ ⁡ D
20 10 19 bitrdi ⊢ K ∈ B ∧ D ∈ A → F ∈ T ⁡ D ↔ F ∈ L ⁡ D ∧ ∀ q ∈ W ⁡ D ∀ r ∈ W ⁡ D q + ˙ F ⁡ q ∩ ⊥ ˙ ⁡ D = r + ˙ F ⁡ r ∩ ⊥ ˙ ⁡ D