Metamath Proof Explorer


Theorem isunit3

Description: Alternate definition of being a unit. (Contributed by Thierry Arnoux, 3-Aug-2025)

Ref Expression
Hypotheses isunit2.b ⊢ B = Base R
isunit2.u ⊢ U = Unit ⁡ R
isunit2.m ⊢ · ˙ = ⋅ R
isunit2.1 ⊢ 1 ˙ = 1 R
isunit3.x ⊢ φ → X ∈ B
isunit3.r ⊢ φ → R ∈ Ring
Assertion isunit3 ⊢ φ → X ∈ U ↔ ∃ y ∈ B X · ˙ y = 1 ˙ ∧ y · ˙ X = 1 ˙

Proof

Step Hyp Ref Expression
1 isunit2.b ⊢ B = Base R
2 isunit2.u ⊢ U = Unit ⁡ R
3 isunit2.m ⊢ · ˙ = ⋅ R
4 isunit2.1 ⊢ 1 ˙ = 1 R
5 isunit3.x ⊢ φ → X ∈ B
6 isunit3.r ⊢ φ → R ∈ Ring
7 1 2 3 4 isunit2 ⊢ X ∈ U ↔ X ∈ B ∧ ∃ u ∈ B X · ˙ u = 1 ˙ ∧ ∃ v ∈ B v · ˙ X = 1 ˙
8 5 biantrurd ⊢ φ → ∃ u ∈ B X · ˙ u = 1 ˙ ∧ ∃ v ∈ B v · ˙ X = 1 ˙ ↔ X ∈ B ∧ ∃ u ∈ B X · ˙ u = 1 ˙ ∧ ∃ v ∈ B v · ˙ X = 1 ˙
9 7 8 bitr4id ⊢ φ → X ∈ U ↔ ∃ u ∈ B X · ˙ u = 1 ˙ ∧ ∃ v ∈ B v · ˙ X = 1 ˙
10 eqid ⊢ mulGrp R = mulGrp R
11 10 1 mgpbas ⊢ B = Base mulGrp R
12 10 4 ringidval ⊢ 1 ˙ = 0 mulGrp R
13 10 3 mgpplusg ⊢ · ˙ = + mulGrp R
14 10 ringmgp ⊢ R ∈ Ring → mulGrp R ∈ Mnd
15 6 14 syl ⊢ φ → mulGrp R ∈ Mnd
16 11 12 13 15 5 mndlrinvb ⊢ φ → ∃ u ∈ B X · ˙ u = 1 ˙ ∧ ∃ v ∈ B v · ˙ X = 1 ˙ ↔ ∃ y ∈ B X · ˙ y = 1 ˙ ∧ y · ˙ X = 1 ˙
17 9 16 bitrd ⊢ φ → X ∈ U ↔ ∃ y ∈ B X · ˙ y = 1 ˙ ∧ y · ˙ X = 1 ˙