Metamath Proof Explorer


Theorem itgeq1d

Description: Equality theorem for an integral. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypothesis itgeq1d.aeqb ⊢ φ → A = B
Assertion itgeq1d ⊢ φ → ∫ A C dx = ∫ B C dx

Proof

Step Hyp Ref Expression
1 itgeq1d.aeqb ⊢ φ → A = B
2 itgeq1 ⊢ A = B → ∫ A C dx = ∫ B C dx
3 1 2 syl ⊢ φ → ∫ A C dx = ∫ B C dx