Metamath Proof Explorer


Theorem itgvol0

Description: If the domani is negligible, the function is integrable and the integral is 0. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Hypotheses itgvol0.1 ⊢ φ → A ⊆ ℝ
itgvol0.2 ⊢ φ → vol * ⁡ A = 0
itgvol0.3 ⊢ φ ∧ x ∈ A → B ∈ ℂ
Assertion itgvol0 ⊢ φ → x ∈ A ⟼ B ∈ 𝐿 1 ∧ ∫ A B dx = 0

Proof

Step Hyp Ref Expression
1 itgvol0.1 ⊢ φ → A ⊆ ℝ
2 itgvol0.2 ⊢ φ → vol * ⁡ A = 0
3 itgvol0.3 ⊢ φ ∧ x ∈ A → B ∈ ℂ
4 mpt0 ⊢ x ∈ ∅ ⟼ B = ∅
5 iblempty ⊢ ∅ ∈ 𝐿 1
6 4 5 eqeltri ⊢ x ∈ ∅ ⟼ B ∈ 𝐿 1
7 0ss ⊢ ∅ ⊆ A
8 7 a1i ⊢ φ → ∅ ⊆ A
9 difssd ⊢ φ → A ∖ ∅ ⊆ A
10 ovolssnul ⊢ A ∖ ∅ ⊆ A ∧ A ⊆ ℝ ∧ vol * ⁡ A = 0 → vol * ⁡ A ∖ ∅ = 0
11 9 1 2 10 syl3anc ⊢ φ → vol * ⁡ A ∖ ∅ = 0
12 8 1 11 3 itgss3 ⊢ φ → x ∈ ∅ ⟼ B ∈ 𝐿 1 ↔ x ∈ A ⟼ B ∈ 𝐿 1 ∧ ∫ ∅ B dx = ∫ A B dx
13 12 simpld ⊢ φ → x ∈ ∅ ⟼ B ∈ 𝐿 1 ↔ x ∈ A ⟼ B ∈ 𝐿 1
14 6 13 mpbii ⊢ φ → x ∈ A ⟼ B ∈ 𝐿 1
15 12 simprd ⊢ φ → ∫ ∅ B dx = ∫ A B dx
16 itg0 ⊢ ∫ ∅ B dx = 0
17 15 16 eqtr3di ⊢ φ → ∫ A B dx = 0
18 14 17 jca ⊢ φ → x ∈ A ⟼ B ∈ 𝐿 1 ∧ ∫ A B dx = 0