Metamath Proof Explorer


Theorem ker2idl

Description: The kernel of a ring homomorphism is a two-sided ideal. (Contributed by Jeff Madsen, 3-Jan-2011) (Revised by AV, 24-Aug-2026)

Ref Expression
Hypotheses ker2idl.i ⊢ I = 2Ideal ⁡ R
ker2idl.0 ⊢ 0 ˙ = 0 S
Assertion ker2idl ⊢ F ∈ R RingHom S → F -1 0 ˙ ∈ I

Proof

Step Hyp Ref Expression
1 ker2idl.i ⊢ I = 2Ideal ⁡ R
2 ker2idl.0 ⊢ 0 ˙ = 0 S
3 eqid ⊢ LIdeal ⁡ R = LIdeal ⁡ R
4 3 2 kerlidl ⊢ F ∈ R RingHom S → F -1 0 ˙ ∈ LIdeal ⁡ R
5 rhmopp ⊢ F ∈ R RingHom S → F ∈ opp r ⁡ R RingHom opp r ⁡ S
6 eqid ⊢ LIdeal ⁡ opp r ⁡ R = LIdeal ⁡ opp r ⁡ R
7 eqid ⊢ opp r ⁡ S = opp r ⁡ S
8 7 2 oppr0 ⊢ 0 ˙ = 0 opp r ⁡ S
9 6 8 kerlidl ⊢ F ∈ opp r ⁡ R RingHom opp r ⁡ S → F -1 0 ˙ ∈ LIdeal ⁡ opp r ⁡ R
10 5 9 syl ⊢ F ∈ R RingHom S → F -1 0 ˙ ∈ LIdeal ⁡ opp r ⁡ R
11 eqid ⊢ opp r ⁡ R = opp r ⁡ R
12 3 11 6 1 2idlelb ⊢ F -1 0 ˙ ∈ I ↔ F -1 0 ˙ ∈ LIdeal ⁡ R ∧ F -1 0 ˙ ∈ LIdeal ⁡ opp r ⁡ R
13 4 10 12 sylanbrc ⊢ F ∈ R RingHom S → F -1 0 ˙ ∈ I