Metamath Proof Explorer


Theorem kerlmhm

Description: The kernel of a vector space homomorphism is a vector space itself. (Contributed by Thierry Arnoux, 7-May-2023)

Ref Expression
Hypotheses kerlmhm.1 ⊢ 0 ˙ = 0 U
kerlmhm.k ⊢ K = V ↾ 𝑠 F -1 0 ˙
Assertion kerlmhm ⊢ V ∈ LVec ∧ F ∈ V LMHom U → K ∈ LVec

Proof

Step Hyp Ref Expression
1 kerlmhm.1 ⊢ 0 ˙ = 0 U
2 kerlmhm.k ⊢ K = V ↾ 𝑠 F -1 0 ˙
3 eqid ⊢ F -1 0 ˙ = F -1 0 ˙
4 eqid ⊢ LSubSp ⁡ V = LSubSp ⁡ V
5 3 1 4 lmhmkerlss ⊢ F ∈ V LMHom U → F -1 0 ˙ ∈ LSubSp ⁡ V
6 2 4 lsslvec ⊢ V ∈ LVec ∧ F -1 0 ˙ ∈ LSubSp ⁡ V → K ∈ LVec
7 5 6 sylan2 ⊢ V ∈ LVec ∧ F ∈ V LMHom U → K ∈ LVec